CODEWITHSUNDEEP
ccontikicooja
H. Almutairi
H. Almutairi

Reputation: 5

Float Calculation in Cooja

I'm using RPL in Contiki 3.0 and I need to make some calculations where the results are float. But instead of giving me the result in float, it is only calculating the integer number for example: 5/2 = 2.0 instead of 2.5. How can I get the right answer? I can not print float or double in Contiki 3.0 so I'm using this code to convert float into a string:

    // Reverses a string 'str' of length 'len'
    void reverse(char* str, int len)
    {
        int i = 0, j = len - 1, temp;
        while (i < j) {
            temp = str[i];
            str[i] = str[j];
            str[j] = temp;
            i++;
            j--;
        }
    }

  
// Converts a given integer x to string str[]. 
// d is the number of digits required in the output. 
// If d is more than the number of digits in x, 
// then 0s are added at the beginning.
int intToStr(int x, char str[], int d)
{
    int i = 0;
    while (x) {
        str[i++] = (x % 10) + '0';
        x = x / 10;
    }
  
    // If number of digits required is more, then
    // add 0s at the beginning
    while (i < d)
        str[i++] = '0';
  
    reverse(str, i);
    str[i] = '\0';
    return i;
}
  
// Converts a floating-point/double number to a string.
void ftoa(float n, char* res, int afterpoint)
{
    // Extract integer part
    int ipart = (int)n;
  
    // Extract floating part
    float fpart = n - (float)ipart;
  
    // convert integer part to string
    int i = intToStr(ipart, res, 0);
  
    // check for display option after point
    if (afterpoint != 0) {
        res[i] = '.'; // add dot
  
        // Get the value of fraction part upto given no.
        // of points after dot. The third parameter 
        // is needed to handle cases like 233.007
        fpart = fpart * powf(10, afterpoint);
  
        intToStr((int)fpart, res + i + 1, afterpoint);
    }
}

I appreciate your help Thanks Hanin

Upvotes: 0

Views: 838

Answers (3)

farhan saleem
farhan saleem

Reputation: 1

I also wanted to print float value in cooja, so I found this solution.

// digits before point
unsigned short d1(float f){
    return((unsigned short)f);
}

// digits after point
unsigned short d2(float f){
    return(1000*(f-d1(f)));
}

int main()
{
  float max = 6.796; 
  printf("max value %u.%u \n", d1(max) , d2(max));
}

Upvotes: 0

kfx
kfx

Reputation: 8537

If you want to print a number as a float, simply print the part before the floating point as an integer, print the dot, and then multiply the part after the floating point with a power of 10 and print it as another integer. For example, if you want to print 6 digits after the floating point, multiply the fractional part with 1000000.

You will need a separate buffer to print the part after the floating point first - the first digit must be nonzero, so the safe option to pad the number with another digit e.g. "1" that you do not print. To do that, simply add the 1.0 to the fractional part before multiplying it.

Here is the complete code:

float f = 5.0 / 2;
char fractional_part[10];
sprintf(fractional_part, "%d", (int)((f - (int)f + 1.0) * 1000000));
printf("%d.%s\n", (int)f, &fractional_part[1]); // prints "2.500000"

Upvotes: 0

Sriswaroop Koundinya
Sriswaroop Koundinya

Reputation: 185

Because 5/2 is a form of integer division, what you put in you get out, meaning that if you put in 5/2 you will only get an integer back, in the form of 2.

To fix this, make your 5/2 is 5/2.0 so that it is read in as a float, and that will make sure that you will get an answer that is a floating-point decimal.

Upvotes: 0

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