CODEWITHSUNDEEP
regexgroovydevopsjenkins-groovy
WhoAmI
WhoAmI

Reputation: 1133

Filter a string in Groovy and do something with the matches

 def aString = '[Something-26607] Updating another.txt [Something2] Updating something.txt [Something2] Updating something.txt fsfsfs'

Is there a way in groovy to get only unique parts between the square brackets and store them in a variable so after I can call them in a for loop. So I will iterate over them

Something-26607
Something2

I have tried:

def matcher = aString =~ (/\[(?<issue>[^]]+)]/)
def result = matcher.find() ? matcher.group('issue') : ""
 print result

but I get only get the first match:

Something-26607

Upvotes: 0

Views: 2207

Answers (1)

The fourth bird
The fourth bird

Reputation: 163217

I have no experience in Groovy, but reading a little bit about the syntax to get an example, you might use a Set and loop the results using a while loop:

def myList = []
def aString = '[Something-26607] Updating another.txt [Something2] Updating something.txt [Something2] Updating something.txt fsfsfs'

def pattern = Pattern.compile("\\[(?<issue>[^]]+)]")
def matcher = pattern.matcher(aString)

while (matcher.find()) {
    myList << matcher.group(1)
}
println myList.toSet()

Output

[Something2, Something-26607]

Groovy demo

Without using a Set, you can also use a negative lookahead to check to get the unique values in the string asserting that what is captured in the group does not occur anymore at the right side.

\\[(?<issue>[^]]+)](?!.*\\1)

Regex demo

Upvotes: 1

Related Questions