CODEWITHSUNDEEP
pythonlistif-statement
newbieZ
newbieZ

Reputation: 31

Why does the if statement not recognize what is in the list?

I want the if statement to correctly compare what is in the list to what the input is in the enter_password variable.

user_password = []
password = input("Enter what you would like your password to be. \n ENTER: ")
user_password.append(password)
print(f"Password created! Your password is: {user_password}")
enter_password = input("Enter password: ")
if enter_password == user_password:
    print("Welcome")
else:
    print(f"{user_password} is wrong password")

Upvotes: 0

Views: 193

Answers (1)

Eagleclaw
Eagleclaw

Reputation: 369

You're appending your user input to a list and you're comparing it with string.

If you're going to check a single password, don't append it to a list, set it to a string aswell. Or if you need to check a password inside a list you can do it like this.

user_password = []
password = input("Enter what you would like your password to be. \n ENTER: ")
user_password.append(password)
print(f"Password created! Your password is: {user_password}")
enter_password = input("Enter password: ")
if enter_password in user_password: # This is the part that i've changed.
    print("Welcome")
else:
    print(f"{user_password} is wrong password")

Upvotes: 2

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