CODEWITHSUNDEEP
regex
JaimeCamargo
JaimeCamargo

Reputation: 363

Regex: find two consonants together but not in a list

I need a regular expression to find two consonants together between two vowels but these consonants should not be in a list:

For instance, my black-list is (br|bl|cn|cr)

between = It's good because 'tw' is not in the list.
abroad = it's wrong because 'br' is in the black-list.

But I need only the two last pair consonant-vowel:

between = I only need 'we' no 'et'.

I have the following regex, but I don't know how to check if the captured consonant is in the list.

"[aeiou]([^aeiou]{2})[aeiou]"

I captured the consonants with "([^aeiou]{2})", but how do I check if the capture "\1" is in the black-list?

Upvotes: 1

Views: 207

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627086

You can use

(?<=[aeiou](?!(?:br|bl|cn|cr))[b-df-hj-np-tv-z])[b-df-hj-np-tv-z][aeiou]
(?<=[aeiou](?!(?:b[rl]|c[nr]))[b-df-hj-np-tv-z])[b-df-hj-np-tv-z][aeiou]

See the regex demo

Details

  • (?<=[aeiou](?!(?:br|bl|cn|cr))[b-df-hj-np-tv-z]) - a positive lookbehind that requires a lowercase ASCII vowel letter and then an ASCII lowercase consonant letter that is not a starting point of a br, bl, cn or cr char sequences
  • [b-df-hj-np-tv-z] - a consonant lowercase ASCII letter
  • [aeiou] - a lowercase ASCII vowel letter

Upvotes: 1

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