Reputation: 1
class Node(object):
def __init__(self, name):
self.name = name
self.neighbors = []
def __repr__(self):
return self.name
A = Node('A')
B = Node('B')
C = Node('C')
D = Node('D')
E = Node('E')
F = Node('F')
G = Node('G')
H = Node('H')
A.neighbors = [B, E, F, G, H]
B.neighbors = [A, C, E, F, H]
C.neighbors = [ B, D, G, H]
D.neighbors = [C, E, G]
E.neighbors = [A, B, D, F]
F.neighbors = [A, B, E, G]
G.neighbors = [A, C, D, F, H]
H.neighbors = [A, B, C, G]
all_nodes = [A, B, C, D, E, F, G, H]
def find_cliques(potential_clique=[], remaining_nodes=[], skip_nodes=[], depth=0):
if len(remaining_nodes) == 0 and len(skip_nodes) == 0:
print('This is a clique:', potential_clique)
return 1
found_cliques = 0
for node in remaining_nodes:
# Try adding the node to the current potential_clique to see if we can make it work.
new_potential_clique = potential_clique + [node]
new_remaining_nodes = [n for n in remaining_nodes if n in node.neighbors]
new_skip_list = [n for n in skip_nodes if n in node.neighbors]
found_cliques += find_cliques(new_potential_clique, new_remaining_nodes, new_skip_list, depth + 1)
# We're done considering this node. If there was a way to form a clique with it, we
# already discovered its maximal clique in the recursive call above. So, go ahead
# and remove it from the list of remaining nodes and add it to the skip list.
remaining_nodes.remove(node)
skip_nodes.append(node)
return found_cliques
total_cliques = find_cliques(remaining_nodes=all_nodes)
print('Total cliques found:', total_cliques)
When illustrated it becomes quite clear there are far more cliques than this. Why is this missing say, [A,B,F] or [A,B,E]?
I'm trying to find all the disjoint cycles of this graph, and I identified the BK algorithm as a necessary preliminary step. But I can't find any good code implementations of it, and I thought this would suffice, but it appears it does not.
Why not?
Upvotes: 0
Views: 146
Reputation: 21
Because the BK algorithm is for finding maximal cliques. A maximal clique is a set of vertices S
such that for any vertex v
, either v
is already in S
, or adding v
to S
would not give you a clique.
Consider the clique {A, B, E, F}
. {A, B, E}
is a subset, and therefore also a clique. Thus, it doesn't help you to get out {A, B, E}
- you could just iterate through all the subsets of the maximal cliques.
Upvotes: 1