CODEWITHSUNDEEP
listhaskell
TheWorstHaskellProger
TheWorstHaskellProger

Reputation: 33

How to create a new list of lists from a list of lists in Haskell?

I've a field made of list of lists like this:

let list1 = ["a", "abcdefgh", "abc"]

I want to get a new field 5x5 such that there could be more then 5 lines or columns, but no less. It must be produced from the previous one by addition spaces ' ' or keeping them as they are, if there are more then 5 symbols. For additional lines no spaces needed. For example:

list2 = ["a    ", "abcdefgh", "abc  ", "     ", "     "]

or:

let list1 = ["a", "abcdefgh", "c", "d", "e", "f"]
list2 = ["a    ", "abcdefgh", "c    ", "d    ", "e    ", "f"]

I thought about map, replicate, and length, but I'm a little bit confused. If it's possible, don't use libs (or use Data.Map only). Thank you

Upvotes: 0

Views: 402

Answers (1)

willeM_ Van Onsem
willeM_ Van Onsem

Reputation: 477533

You need to determine the length of the strings. You can do this for example with a lambda expression, so then the mapping looks like:

func :: [String] -> [String]
func mylines = map (\x -> … ) linesOfFiles ++ replicate (5-length mylines) (replicate 5' ')

where x is thus string that will be mapped, and … is an expression to what that value is mapped. I leave filling in … as an exercise.

Usually it is better not to work with length: length takes linear time, and for infinite lists, this will even get the program into an infinite loop.

You can work with recursion to perform padding, something like:

padding :: Int -> a -> [a] -> [a]
padding 0 _ xs = …
padding n x [] = …
padding n x (x:xs) = …

Upvotes: 1

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