Reputation: 1
#include <stdio.h>
int main(){
int H, W, X, Y, cont=1, j=0, x, y;
scanf("%d %d %d %d", &H, &W, &X, &Y);
char matriz[H][W + 1];
for(int i=0; i<H; i++){
scanf("%s", matriz[i]);
}
printf("%s", matriz[3]);
while(j<4){
while(1){
y=y - 1;
if(matriz[X][Y]==matriz[x][y])
cont++;
else
break;
}
j++;
}
return 0;
}
hello I wanted to know why my code does not want to run that first printf, giving the error: "Segmentation fault (core dumped)" and if I remove everything below printf it will work again
Upvotes: 0
Views: 103
Reputation: 23
Here when you give segmentation fault it means you are going out of the allocated storage for ((martiz[][])). for example:
if we have an array names x[4],
then we want to print x[5],
you will receive segmentation fault.
So look at your Code and find the line that program going out of allocated space. otherwise, notice that you should initialize your data types when you define them.
Upvotes: 0
Reputation:
x
and y
are not initialized so you are subject to undefined behavior.
Upvotes: 1