Reputation: 483
I need to display on my single page, each taxonomy name and image. i have 10 different image for taxonomy : 'brique'
It's ok for the name but i can't display image
For the image
<?php
$tax = 'brique';
$terms = get_terms( $tax, $args = array(
'hide_empty' => false, // do not hide empty terms
));
foreach( $terms as $term ) {
$term_link = get_term_link( $term );
$image = get_field('visuel' . $term_id );
if( $term->count > 0 ) {
echo '<a href="' . esc_url( $term_link ) . '">';
echo '<img src="' . $image['url'] . '" alt="' . $image['alt'] .'">';
echo $term->name .'</a>';
} elseif( $term->count !== 0 ) {
echo '' . $term->name .'';
}
}
?>
Upvotes: 0
Views: 215
Reputation: 11282
Try the below code. first, you need to pass taxonomy
Since 4.5.0, taxonomies should be passed via the ‘taxonomy’ argument in the $args array:
you can check here get_terms()
in get_field
you have pass second parameter as term_id
or $term object
<?php
$tax = 'brique';
$terms = get_terms( array(
'taxonomy' => $tax,
'hide_empty' => false,
) );
foreach( $terms as $term ) {
$term_link = get_term_link( $term );
$image = get_field( 'visuel', $term );
if( $term->count > 0 ) {
echo '<a href="' . esc_url( $term_link ) . '">';
echo '<img src="' . $image['url'] . '" alt="' . $image['alt'] .'">';
echo $term->name .'</a>';
} elseif( $term->count !== 0 ) {
echo '' . $term->name .'';
}
}
?>
Upvotes: 1