CODEWITHSUNDEEP
python
D_00
D_00

Reputation: 1513

Minimum and maximum of two lists using Python

Let's say I have two lists (containing 2D positions):

pos1 = [100, 400]
pos2 = [200, 300]

Now I want to store the min x and the min y of these positions into min and max:

min_ = [min_x, min_y]
max_ = [max_x, max_y]

# in this case:

min_ = [100, 300]
max_ = [200, 400]

Actually, I am using a code like this:

min_ = []
max_ = []

min_.append(min(pos1[0], pos2[0]))
min_.append(min(pos1[1], pos2[1]))
max_.append(max(pos1[0], pos2[0]))
max_.append(max(pos1[1], pos2[1]))

Is there a more efficient way to do that?

Upvotes: 0

Views: 72

Answers (3)

Silvio Mayolo
Silvio Mayolo

Reputation: 70307

If you're doing a lot with coordinates, you'll find numpy makes a lot of these sorts of things more ergonomic.

import numpy as np

pos1 = np.array([100, 400])
pos2 = np.array([200, 300])

min_ = np.min([pos1, pos2], 0)
max_ = np.max([pos1, pos2], 0)

Upvotes: 1

Marco
Marco

Reputation: 46

Don't use keywords like min and max for variable names. You could use list-comprehension and zip:

minimum_values = [min(x,y) for x,y in zip(pos1, pos2)]

Upvotes: 1

Ivaylo Strandjev
Ivaylo Strandjev

Reputation: 70989

Maybe this:

min_ = [min(first, second) for first, second in zip(pos1, pos2)]
max_ = [max(first, second) for first, second in zip(pos1, pos2)]

By the way same but (maybe) a bit less readable:

min_ = [min(coords) for coords in zip(pos1, pos2)]
max_ = [max(coords) for coords in zip(pos1, pos2)]

NOTE: in terms of efficiency the two solutions are probably comparable this one simply avoids some code repetition.

Upvotes: 1

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