Reputation: 1
Working in SSMS. Based on a value in one column I want to count the number of different occurrences in another column. How would I go about to do that?
Basically for each unique value in Column 1, how many combinations of Column 2 can be found?
So if table looks like this:
Column 1 | Column 2 |
---|---|
A | 1 |
A | 1 |
A | 1 |
B | 1 |
B | 2 |
B | 3 |
C | 2 |
C | 2 |
C | 3 |
Desired output would then be:
A = 1
B = 3
C = 2
Upvotes: 0
Views: 34
Reputation: 350
Use COUNT(DISTINCT)
for this case with GROUP BY
:
SELECT Col1, COUNT(DISTINCT Col2)
FROM YourTable
GROUP BY Col1
Upvotes: 2
Reputation: 5225
WITH CTE(Column1,Column2) AS
(
SELECT 'A', 1 UNION ALL
SELECT 'A' , 1 UNION ALL
SELECT 'A' , 1 UNION ALL
SELECT 'B' , 1 UNION ALL
SELECT 'B' , 2 UNION ALL
SELECT 'B' , 3 UNION ALL
SELECT 'C' , 2 UNION ALL
SELECT 'C' , 2 UNION ALL
SELECT 'C' , 3
)
SELECT C.COLUMN1,COUNT(DISTINCT C.COLUMN2)CNTT
FROM CTE AS C
GROUP BY C.Column1
CTE is an example you provided. Please replace reference to it with reference to your table
Upvotes: 0