Sousuke
Sousuke

Reputation: 1293

ElementReference to conditionally created element in Blazor

I'm trying to set focus to input control which is conditionally rendered. I'm setting ElementReference but it's id and context are both null.

<button @onclick="ToggleInput">Show input</button>
@if(showInput) {
    <input @ref="inputRef" type="text"/>
}

@code {
    private ElementReference inputRef;
    private bool showInput;

    async void ToggleInput() {
        showInput = !showInput;

        await inputRef.FocusAsync();
    }
}

When I press the button it shows this error in console:

System.InvalidOperationException: ElementReference has not been configured correctly

Full error message:

enter image description here

Working example with error https://blazorrepl.com/repl/wbueaMPK28hf2NNv09

Upvotes: 6

Views: 5733

Answers (4)

Matias Masso
Matias Masso

Reputation: 1970

A slightly cleaner solution:

<button @onclick="ToggleInput">Show input</button>
@if(showInput) {
    <input @ref="inputRef" type="text"/>
}

@code {
    private ElementReference inputRef;
    private bool showInput;

    async void ToggleInput() {
        showInput = !showInput;
        await InvokeAsync(StateHasChanged);
        await inputRef.FocusAsync();
    }
}

Upvotes: 0

Adrian
Adrian

Reputation: 111

It's not the perfect solution either, more like a workaround, but the following worked for me:

<button @onclick="ToggleInput">Show input</button>
@if(showInput) {
    <input @ref="inputRef" type="text"/>
}

@code {
    private ElementReference inputRef;
    private bool showInput;

    async void ToggleInput() {
        showInput = !showInput;
        StateHasChanged();
        
        await Task.Run(() =>
        {
            if(inputRef.Context != null) inputRef.FocusAsync();
        });
    }
}

In my tests, the context was never null, so it probably wouldn't need the check. But I prefer that the focus is not set than that an exception would be thrown.

Upvotes: 2

Nikki9696
Nikki9696

Reputation: 6348

This seems to work and didn't have to be a separate component. I stuck it right on the start page.

<button @onclick="ToggleInput">Show input</button>
@if (showInput)
{
    <input @ref="inputRef" type="text" />
}

@code {
    private ElementReference inputRef;
    private bool showInput;

    protected async override Task OnAfterRenderAsync(bool firstRender)
    {
        if (showInput) await inputRef.FocusAsync();
    }

    void ToggleInput()
    {
        showInput = !showInput;
    }
}

Upvotes: 9

Brian Parker
Brian Parker

Reputation: 14523

Move the input box to another component. Then you can then hook into the lifecycle of the component and call .FocusAsync after it has rendered.

https://blazorrepl.com/repl/cluoEsvU59fl8zYM22

Upvotes: 2

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