CODEWITHSUNDEEP
c++classfriend-function
Parshant Khichi
Parshant Khichi

Reputation: 87

Why friend function without argument is not working?

 #include<iostream>
    using namespace std;
    
    class complex{
        private:
        int x;
    
        public:
        friend void fun(void);
    };
    
    void fun(void)
    {
        cout<<"outside "<<endl;
    }
    int main()
    {
        complex c1;
        c1.fun();
        return 0;
    }

why I'm getting the following error which says that 'class complex' has no member named 'fun' in VS code

36_friend_function.cpp: In function 'int main()':
36_friend_function.cpp:19:8: error: 'class complex' has no member named 'fun'
     c1.fun();
        ^~~

Upvotes: 0

Views: 87

Answers (1)

Devolus
Devolus

Reputation: 22104

The function fun is a friend of complex, which means it is allowed to use internals of that object. It is not part of the object though, so you can not call it via the object.

You must call funjust like any other function, which it is.

Example:

void fun(complex &c)
{
    // fun is a friend so it can access private member x.
    cout << "outside " << c.x << endl;
}

int main()
{
    complex c1;
    fun(c1);
    return 0;
}

Upvotes: 1

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