CODEWITHSUNDEEP
pythonlistdictionaryindexing
hannah m
hannah m

Reputation: 21

Find the index of a nested dict within a list base on the dict's nested value

i have a list of dicts

[{"id":1, "name": "jane", "contact": {"email": "[email protected]", "phone": "8179482938"}},
{"id":2, "name": "john", "contact": {"email": "[email protected]", "phone": "8179482937"}},
{"id":3, "name": "june", "contact": {"email": "[email protected]", "phone": "8179482936"}}]

how can i find the index of jane given only her phone number (8179482938)?

Upvotes: 0

Views: 42

Answers (3)

Tim Roberts
Tim Roberts

Reputation: 54698

It's rather straightforward. You loop through the list until you find the one you want.

def get_name(phone):
    for i, row in enumerate(list_of_dicts):
        if row['contact']['phone'] == phone:
            return i

Upvotes: 1

Andrej Kesely
Andrej Kesely

Reputation: 195438

To get an index, you can do (lst is your list from question):

idx = next(i for i, d in enumerate(lst) if d["contact"]["phone"] == "8179482938")
print(idx)

Prints:

0

Upvotes: 0

ferdy
ferdy

Reputation: 7716

This:

book = [{"id":1, "name": "jane", "contact": {"email": "[email protected]", "phone": "8179482938"}},
{"id":2, "name": "john", "contact": {"email": "[email protected]", "phone": "8179482937"}},
{"id":3, "name": "june", "contact": {"email": "[email protected]", "phone": "8179482936"}}]

for item in book:
    if item['contact']['phone'] == '8179482938':
        print(item['id'])

Upvotes: 0

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