Reputation: 793
I am trying to apply the accepted solution to this question to the problem below but stupidly I cannot:
In:
increment='increment'
[f'{level_A}_{level_B}_{level_C}_{increment}'
for level_A, rng in [(5, list(range(1,3))), (6, list(range(1,3)))]
for level_B in rng
for level_C in range(1, 5)]
Out:
['5_1_1_increment',
'5_1_2_increment',
'5_1_3_increment',
'5_1_4_increment',
'5_2_1_increment',
'5_2_2_increment',
'5_2_3_increment',
'5_2_4_increment',
'6_1_1_increment',
'6_1_2_increment',
'6_1_3_increment',
'6_1_4_increment',
'6_2_1_increment',
'6_2_2_increment',
'6_2_3_increment',
'6_2_4_increment']
Where the increment
values need to be 1,2,3,..15,16. Importantly, I need to do this in a single line (ie no variable definition outside the comprehension) and ideally without any imports (like in the original question's accepted answer)
Upvotes: 0
Views: 106
Reputation: 2343
Use walrus operator for increment.
>>> increment=0
>>> [f'{level_A}_{level_B}_{level_C}_{(increment:=increment+1)}'
... for level_A, rng in [(5, list(range(1,3))), (6, list(range(1,3)))]
... for level_B in rng
... for level_C in range(1, 5)]
which gives me:
['5_1_1_1', '5_1_2_2', '5_1_3_3', '5_1_4_4', '5_2_1_5', '5_2_2_6', '5_2_3_7', '5_2_4_8', '6_1_1_9', '6_1_2_10', '6_1_3_11', '6_1_4_12', '6_2_1_13', '6_2_2_14', '6_2_3_15', '6_2_4_16']
Upvotes: 2
Reputation: 6930
Since you need to number them after you generate the combinations, you need to use nested generators/comprehensions:
enumerate(..., start=1)
[
f"{level_A}_{level_B}_{level_C}_{increment}"
for increment, (level_A, level_B, level_C) in enumerate(
(
(A, B, C)
for A, rng in [(5, list(range(1, 3))), (6, list(range(1, 3)))]
for B in rng
for C in range(1, 5)
),
start=1,
)
]
Upvotes: 1