Reputation: 47
I have the time and the values in the data base. I need to calculate for a given month the average during each hour i.e.
YYYY-mm-dd (the day can be omitted)
2021-01-01 00:00:00 value=avg(values from 00:00:00 until 00:59:59 for every day of this month at this hour interval)
2021-01-01 01:00:00 value=avg(values from 01:00:00 until 01:59:59 idem as above)
...
2021-01-01 23:00:00 value=avg(values from 23:00:00 until 23:59:59)
2021-02-01 00:00:00 value=avg(values from 00:00:00 until 00:59:59)
2021-02-01 01:00:00 value=avg(values from 01:00:00 until 01:59:59)
...
2021-02-01 23:00:00 value=avg(values from 23:00:00 until 23:59:59)
...
Upvotes: 0
Views: 1246
Reputation: 108651
You can use date_trunc('hour', datestamp)
in a GROUP BY statement, something like this.
SELECT DATE_TRUNC('hour', datestamp) hour_beginning, AVG(value) average_value
FROM mytable
WHERE datestamp >= '2021-01-01'
AND datestamp < '2021-02-01'
GROUP BY DATE_TRUNC('hour', datestamp)
ORDER BY DATE_TRUNC('hour', datestamp)
To generalize, in place of DATE_TRUNC
you can use any injective function.
You could use
to_char(datestamp, 'YYYY-MM-01 HH24:00:00')
to get one result row per hour for every month in your date range.
SELECT to_char(datestamp, 'YYYY-MM-01 HH24:00:00') hour,
AVG(value) average_value
FROM mytable
GROUP BY to_char(datestamp, 'YYYY-MM-01 HH24:00:00')
ORDER BY to_char(datestamp, 'YYYY-MM-01 HH24:00:00')
Upvotes: 2