CODEWITHSUNDEEP
c++vectoreigen
Christian Farina
Christian Farina

Reputation: 47

Converting an Eigen::VectorXd to an std::vector<double>

As the title says, I am trying to convert an Eigen::VectorXd to an std::vector. The vector is obtained by diagonalizing a matrix and then taking the first eigenvector of the process.

#include <iostream>
#include <vector>
#include <cmath>
#include <iomanip>
#include <Eigen/Dense>

using namespace std;
using namespace Eigen;

using namespace std;

int main()
{
    vector<double> vec;
    MatrixXd ones = MatrixXd::Ones(3,3);
    VectorXd firstEvector;
    SelfAdjointEigenSolver<MatrixXd> es(ones);
    firstEvector = es.eigenvectors().col(1);
    cout << "The first eigenvector of the 3x3 matrix of ones is:" << endl << firstEvector << endl;
    vec(&firstEvector[0], firstEvector.data() + firstEvector.cols()*firstEvector.rows());
    return 0;
}

I thought this was the way to do it, however, it doesn't work. I get the following error.

C:\CBProjects\eigenVectors\main.cpp|20|error: no match for call to '(std::vector<double>) (Eigen::DenseCoeffsBase<Eigen::Matrix<double, -1, 1>, 1>::Scalar*, Eigen::PlainObjectBase<Eigen::Matrix<double, -1, 1> >::Scalar*)'|

I can't see what I am doing wrong. Any help would be greatly appreciated.

Upvotes: 3

Views: 4035

Answers (1)

RHertel
RHertel

Reputation: 23788

You are using a constructor syntax for the std::vector vec although the vector was already declared. That doesn't work.

There are two efficient possibilities to copy the content of an Eigen::VectorXd into a std::vector<double>. You can either construct a new std::vector vec2, like this:

vector<double> vec2(firstEvector.data(), firstEvector.data() + firstEvector.size());

or use the previously declared vector vec and transfer the data from the Eigen::VectorXd by using Eigen::Map. But in that case the std::vector first needs to be resized:

vec.resize(firstEvector.size());
Map<VectorXd>(vec.data(), vec.size()) = firstEvector;

Upvotes: 6

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