CODEWITHSUNDEEP
python
EggCoder
EggCoder

Reputation: 37

I made a dictionary, I am struggling with print x number of times that user inputs

This is my dictionary:

def get_dic(filename):
count = 0
db = {}
filename = "words.txt"


with open(filename, "r") as infile:
    for line in infile:
        if line:
            eng_words, spa_words = line.rstrip().split(":")
            key = eng_words
            val = spa_words.split(",")
            db[key] = val
            count += 1
            print(count, "entries found.")
            return db

this is the file it reads from and converts it to a dictionary:

library:la biblioteca
school:el colegio,la escuela
restaurant:el restaurante
movie theater:el cine
airport:el aeropuerto
museum:el museo
park:el parque
university:la universidad
office:la oficina,el despacho
house:la casa

Now I wanna call my db and make a "quiz" game using random() method after user inputs a number from 1 to 10. Since my list is only 10 lines.

import random

def main():

    db = get_dic(filename)
    random.shuffle(db)

    for keyword in db(10):
        display = "{}"

        print(display.format(keyword))
        userinput = input("Enter 1 equivalent Spanish word(s). Word [1]: ")
        print(db[keyword])
        print(" ")

        if userinput == (db[key]):
            print("correct!")
            correct += 1

If input is "5", how do I get the program to print 5 words?

And I wanna return the score "correct" into another function that is not main(). Which will later write the score to a seperate .txt file, Is this possible? Do I just "return correct" and call it in a function like usual? I've only seen codes call function in "def main():"

output example if input choosen is 2:

English word: museum
Enter 1 equivalent Spanish word(s). Word [1]: el museo
Correct!
---
English word: school 
Enter 2 equivalent Spanish word(s). Word [1]: el colegio 
Word [2]: la escuela 
Correct!

Upvotes: 0

Views: 77

Answers (2)

Zachiah
Zachiah

Reputation: 2627

to validate the input you can also do

def get_num(text,err_text,verify):
    try:
        the_input = int(input(text))
        if verift(the_input):
            return the_input
        else:
            print(err_text)
            return get_num(text,err_text)
    except:
        print(err_text)
        return get_num(text,err_text)

#...

rounds = get_num('Enter a number of rounds (1-10): ', 'please enter an integer between 1 and 10', verify=lambda x:x>0 and x <11)

Upvotes: 0

quamrana
quamrana

Reputation: 39354

This may be what you want. I ask the user how many rounds first. (I have not validated this input, though)

def main():
    db = get_dic(filename)
    keys = list(db.keys())
    random.shuffle(keys)
    
    rounds = int(input('Enter a number of rounds (1-10): '))
    correct = 0
    for keyword in keys[:rounds]:
        print(keyword)
        userinput = input("Enter 1 equivalent Spanish word(s). Word [1]: ")
        print(db[keyword])
        print(" ")

        if userinput == (db[keyword]):
            print("correct!")
            correct += 1
    return correct

correct = main()
print(f'{correct} answers correct')

Upvotes: 3

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