Reputation: 149
I am sending form data to a c# controller using AJAX, however I don't know how to access the data inside the controller. I am trying to pass the form data into the controller as a Person object but I am just returning system.Models.Person. I am new to C# so any help would be greatly appreciated, thanks a lot.
Javascript
$('#myForm').submit(function(e){
e.preventDefault();
const formData = new FormData(e.target);
$.ajax({
url: '/Home/GetFormData',
type: 'POST',
data: {formData: formData},
success: function(resultData){
console.log(resultData)
},
error: function(){
//do something else
}
})
}
Model
public class Person
{
public string name { get; set; }
public string age { get; set; }
}
Controller
public string GetFormData(Person formData)
{
string name = formData.name.ToString();
return name;
}
Upvotes: 3
Views: 3267
Reputation: 197
The following post will help you
Post Data Using jQuery in ASP.NET MVC
Your code should be
Model class Person.cs
public class Person
{
public string name { get; set; }
public string age { get; set; }
}
jQuery function to get the form data, I am assuming here you have submit button on your form
$(document).ready(function () {
$("#btnSave").click(function () { //Your Submit button
$.ajax(
{
type: "POST", //HTTP POST Method
url: "Home/GetFormData", // Controller/View
data: { //Passing data
name: $("#txtname").val(), //Reading text box values using Jquery
age: $("#txtage").val(),
}
});
});
});
Your HomeController method
[HttpPost]
public ActionResult GetFormData(Person obj)
{
string name = obj.name;
string age = obj.age;
//Once you have data here then you can pass anywhere i.e. database or some other method
return View();
}
Form values in the controller
Let me know, if any clarification required.
Upvotes: 2
Reputation: 9131
Use serialize if you will send form values:
$form = $(this).serialize();
Use FormData if you be sending a file for upload and alike.
And on your data declaration, set it as is (without declaring it as a literal JS object)
data: $form
The final code would look like this:
$('#myForm').submit(function(e){
e.preventDefault();
$form = $(this).serialize();
$.ajax({
url: '/Home/GetFormData',
type: 'POST',
data: $form,
success: function(resultData){
console.log(resultData)
},
error: function(){
//do something else
}
})
Upvotes: 3