CODEWITHSUNDEEP
djangodjango-urls
Dan
Dan

Reputation: 6583

Django - Access session in urls.py

I'm trying to use a ListView to avoid creating a view for what should be quite a simple page. Basically I want to list a set of objects related to the current user, however I'm not sure how to access the session values from within the urls.py.

What I have looks something like this:

 (r'^myrecords/$', ListView.as_view(
        queryset=Record.objects.filter(CURRENT LOGGED IN USER),
        context_object_name='record_list',
        template_name='records.html')),

What do I need to do?

Also is there any way to apply the login_required decorator to this?

Any advice would be greatly appreciated.

Thanks.

Upvotes: 3

Views: 875

Answers (1)

Ismail Badawi
Ismail Badawi

Reputation: 37227

See the docs on dynamic filtering.

You should subclass ListView and override the get_queryset method. When the class-based view is called, self is populated with the current request (self.request) as well as anything captured from the URL (self.args, self.kwargs).

from django.views.generic import ListView
from myapp.models import Record

class MyRecordsListView(ListView):
    context_object_name = 'record_list'
    template_name = 'records.html',

    def get_queryset(self):
        return Record.objects.filter(user=self.request.user)

There's also documentation for decorating class-based views. Basically you can just decorate the result of as_view in your urls.py:

(r'^myrecords/$', login_required(MyRecordsListView.as_view())),

Upvotes: 4

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