php filter phrase

Question

How to filter phrase use php? Can anyone give me a function call?

for example, If I want filter the phrase 'no' 'this' from a sentence There are no user contributed notes for this page.

So that the sentence return like There are user contributed notes for page. Thanks.

<?php
function filterBadWords($str)
{
    $badwords = array('no','this');
    $replacements = " ";
    foreach ($badwords AS $badword)
    {
          $str = eregi_replace($badword, str_repeat(' ', strlen($badword)), $str);
    }  
    return $str;
} 

$string = "There are user contributed notes for page.";
print filterBadWords($string); // this will filter `no` from `notes`
?>

Answer 1

$text = preg_replace('/\b(?:no|this)\b ?/i', '', $text);

Edit:

Now it removes a space if it finds one after the word, so that you don't end up with two spaces in a row.

$text = 'There are no user contributed notes for this page.';
$text = preg_replace('/\b(?:no|this)\b ?/i', '', $text);
echo $text;

Outputs: There are user contributed notes for page.

Update

If you want to use an array to make it easier to manage filtered words you could do this:

function filterWords($string){
    $bad_words = array('no', 'this');
    return preg_replace('/\b(?:'.implode('|', $bad_words).')\b ?/i', '', $string);
}

echo filterWords('There are no user contributed notes for this page.');

Answer 2

Use str_replace

str_replace(array('no', 'this'), '', $text);