CODEWITHSUNDEEP
php
Ekky Ardian
Ekky Ardian

Reputation: 5

PHP | Make a validation check whether the number has a decimal point == x.00 or not

Em, I don't know how to explain this. I hope you'll get the point.

I've variables:

$a = 10; //int
$b = 2.5; //float
$c = $a * $b; //I know this return will be float: 25

From those variables, I want to make a statement as follows:

if (//the value of $c have a decimal point == x.00) {
    echo $c;
} else {
    echo '';
}

Did you get it? What I want is that when the decimal point of $c is x.00 (like 25.00, 10.00, etc), the $c will be printed. But if the decimal point is NOT x.00 (eg 25.50, 25.7, etc) then $c will NOT be printed.

I've read some references but still don't understand how to do it.

Thank you. I hope you understand what I mean.

Upvotes: 0

Views: 618

Answers (3)

AbraCadaver
AbraCadaver

Reputation: 78994

Much easier. Just check if the integer of the number is equal == to the number:

if ((int)$c == $c) {
    echo $c;
} else {
    echo '';
}

Upvotes: 0

Dr M L M J
Dr M L M J

Reputation: 2397

You can try like below.

<?php
  function is_decimal_exist( $value ) {
     return is_numeric( $value ) && floor( $value ) != $value;
  }

   $my_value = "10.00";
      

   if( is_decimal_exist ( $my_value ) ) {
       echo ''; // Decimal Present, Do Not Print $my_value
   }else{
       echo $my_value; // Print $my_value
   }
?>

Upvotes: 0

James
James

Reputation: 620

PHP has is_integer() - https://www.php.net/manual/en/function.is-integer.php

Or if you want to check manually, then you can compare against the rounded down (floor) and rounded up (ceil) values:

if ($a==Floor($a) && $a==Ceil($a)){
 // Whole Number
} else {
 // Has decimal point value
}

Upvotes: 1

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