CODEWITHSUNDEEP
javascriptjson
Bruno Morgado
Bruno Morgado

Reputation: 507

Help with JSON iteration

I'm trying to retrieve some data from a JSON response, but this doesn't seem to work:

My javascript code:

  function recommend(response){

    var recommendedList = eval('(' + response.responseText + ')');

    $H(recommendedList).each(function(item){
          alert(item.artist);
        });     
  }

What I want is to retrieve each artist values from the JSON response.

and the JSON response is of the format:

[
 {"artist":"artist1","location":{"lat":"50.952226","lng":"5.34832","ID":28}},
 {"artist":"artist2","location":{"lat":"52.362287","lng":"4.883965","ID":32}},
  ...
]

A little help would be great. Thanks!

Upvotes: 0

Views: 203

Answers (4)

Nikolay Fominyh
Nikolay Fominyh

Reputation: 9256

Avoid framework features when you need simple things. 

for(i=0; i<recommendedList.length; i++) { 
    alert(recommendedList[i].artist);
}

Upvotes: 1

pimvdb
pimvdb

Reputation: 154918

http://www.prototypejs.org/api/hash/each

Pairs are passed as the first argument of the iterator, in the form of objects with two properties:

key, which is the key name as a String

value, which is the corresponding value (and can, possibly, be undefined)

So your item is actually the key. Instead, iterate like:

$H(recommendedList).each(function(key, item){
      alert(item.artist);
    });

Upvotes: 0

Pointy
Pointy

Reputation: 413884

Guessing from the "$H()" that you're using prototype, I'd just get rid of that "$H()" because the array should already be iterable.

recommendedList.each(function(item) {
  alert(item.artist);
});

Upvotes: 1

aroth
aroth

Reputation: 54846

I'm not sure what your $H() function is supposed to be doing (and its existence makes me very sad), but this framework-agnostic snippet seems to get the job done:

for (var index = 0; index < recommendedList.length; index++) {
    alert(recommendedList[index].artist);
}

Here is a working example: http://jsfiddle.net/VgPy5/

Also, I'm sure you're going to be chastised for using eval() like that. You might consider using JSON.parse() instead.

Upvotes: 3

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