CODEWITHSUNDEEP
pythonmathsympysolver
Timmy Diehl
Timmy Diehl

Reputation: 409

How to solve for a second degree term in an equation with SymPy

My equation is ax = ln(ec-b/y)
How can I find what x*y equals in python? I've tried using SymPy.solve, but it doesn't allow me to solve for a term. Thanks in advance.

Upvotes: 0

Views: 210

Answers (1)

smichr
smichr

Reputation: 18939

If you solve for y = f(x) then y*x = x*f(x). So these two steps in SymPy are:

>>> from sympy.abc import a,b,c,x,y
>>> from sympy import solve, Eq
>>> solve(Eq(a*x , ln(exp(c-b)/y)),y)
[exp(-a*x - b + c)]
>>> _[0]*x # == y*x
x*exp(-a*x - b + c)

You can solve for any subexpression, but when it is not a symbol, it will be interpreted literally as if you solved for u after replacing the sub-expression with u:

>>> solve(x*y - 1/x, x*y)
[1/x]

In your expression there is no x*y so that's why an attempt to naively solve for it fails.

Upvotes: 1

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