CODEWITHSUNDEEP
python
TobeT
TobeT

Reputation: 5

Python - Remove quotation marks from list

I have a dataframe with a list of numbers. When printing the list there are quotation marks in the front and at the end which I want to remove. I'm unable to replace them with the replace function.

a = df.iloc[0]['ids']
b = [a]
b (Output) 
['2769734487041924, 7608779650164612'] <-- one quotation mark at beginning and end

What I want (created manually):

row_ids = [1234, 4567]
row_ids (Output)
[1234, 4567] <-- That's the format I want to get the list to, without the quotation marks

Both b and row_ids data type comes back as 'list' so there must be a way to have the list without the quotation marks.

Upvotes: 0

Views: 824

Answers (2)

The.B
The.B

Reputation: 381

Parse the string and split, Then use base ten to convert it as int.

lst = ['2769734487041924, 7608779650164612']
lst2 = []

for i in "".join(lst).split(","):
    lst2.append(int(i, base=10))
print(lst2)

Upvotes: 0

Joffan
Joffan

Reputation: 1480

I think a is a string so to get b as a list of integers from that you need

b = list(map(int, a.split(",")))

Upvotes: 3

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