CODEWITHSUNDEEP
mathassemblytrigonometrynumerical-methods
Ciganeshima
Ciganeshima

Reputation: 67

arctangent implementation in TMS320C55X

I'm learning arctangent implementation in TMS320C55x this is the source code:


;* AR0   assigned to _x
;* AR1   assigned to _r
;* T0   assigned to _nx
        PSH     T3
     || BSET    FRCT            ;fractional mode
    SUB #1, T0          ;nx-1
    MOV T0, BRC0        ;repeat nx times
        MOV     #2596 << #16, AC3       ; AC3.Hi = C5
        MOV #-9464 << #16, AC1  ; AC1.Hi = C3
    MOV #32617 << #16, AC2  ; AC2.Hi = C1
*
* Note: loading T3 on the instruction before a multiply that uses it will
* cause a 1-cycle delay.
*
    MPYMR   T3=*AR0+, AC3, AC0      ; (Prime the Pump)
    
     || RPTBLOCAL   loop1-1
            MACR    AC0, T3, AC1, AC0
            MPYR    T3, AC0
          ||MOV *AR0+, T1               ; (for next iteration)
            MACR    AC0, T3, AC2, AC0
            MPYR    T3, AC0
              ||MOV T1, T3
            MOV HI(AC0), *AR1+      ;save result
          ||MPYR    T1, AC3, AC0            ; (for next iteration)
loop1:

        POP     T3
     || BCLR    FRCT            ;return to standard C
    MOV #0, T0          ;return OK value (no possible error)
     || RET

where _x is vector of input and _r is output. nx is the number of elements. The question is about constants that assigns to AC3, AC1, AC2. I guess it is coefficients for polynomial approximation but i don't understand how to calculate them

Upvotes: 3

Views: 102

Answers (1)

dxiv
dxiv

Reputation: 17668

I do not follow the assembly code, but I could guess where those magic coefficients come from.

The code comments suggest C1, C3, C5 are coefficients of a polynomial approximation, and arctan is an odd function, so its Taylor expansion around 0 has indeed only odd powers of x. Comparing C1 = 32617 to 1 in the Taylor expansion y = x - 1/3 x^3 + 1/5 x^5 - 1/7 x^7 + ..., and given the computational context, this further suggests that the result of the calculation is scaled by 2^15 = 32768.

It turns out that y = (32617 x - 9464 x^3 + 2596 x^5) / 32768 is in fact a pretty good approximation of arctan(x) over the interval [-1, 1]. As shown below (verified in wolfram alpha) the largest absolute error of the approximation is less than 1/1000, and is negligible at the endpoints x = ±1 corresponding to y = ±π/4, which is probably desirable in graphics calculations.

enter image description here

As to how the coefficients were actually derived, a crude polynomial best-fit using just 9 control points gives a polynomial y = 32613 x - 9443 x^3 + 2573 x^5 with coefficients already close to the ones used in the posted code. More control points and/or additional conditions to minimize the error at the end points would result in slightly different coefficients, but it's hard to guess how to exactly match the ones in the code without any documentation or clues about the optimization criteria being actually used there.

enter image description here

Upvotes: 5

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