Reputation: 4803
I have developed watchOS app that is only for Apple Watch not integration with iPhone app. From that need to open Apple's default app. such as :
On iPhone we are open any app via URLScheme
or open(url:)
, but how can we achieve same functionality on watchOS?
on iPhone :
let url = "abc.com"
if UIApplication.shared.canOpenURL(url) {
UIApplication.shared.open(URL, options: nil) { (finished) in
}
}
Upvotes: 0
Views: 176
Reputation: 5220
There is no equivalent on WatchKit
. You can use openSystemURL(_:) to make a call or send a message, but You can't open another app.
Upvotes: 1