CODEWITHSUNDEEP
pythonloopssyntax
hungggggggggggg
hungggggggggggg

Reputation: 23

Why new error appears at the next coding line when putting a comma at the end of a certain line?

I'm quite new with coding. I need your help. I did an exercise and hit the error. The code is like this:

def isAnagram(s,t):  
    if len(s)!=len(t):        
        return False
    else:    
        list_t = sorted(list(set(t))
        list_s = sorted(list(set(s))
        if list_s != list_t:            
            return False
        else:
            i=0
            j=[]
            k=[]
            for i in range len(list_s):
                j.append(list_s.count(list_s[i]))
                k.append(list_t.count(list_t[i]))
                i=i+1
                if j!=k:
                    return False
                else:                      
                      return True

And I get this error

 File "<ipython-input-43-5ac86c9b9c40>", line 7
    list_s = sorted(list(set(s))
    ^
SyntaxError: invalid syntax

If I put a comma at the end of 5th line, then I receive a new error:

 File "<ipython-input-44-6a66b63cb96e>", line 8
    if list_s != list_t:
                       ^
SyntaxError: invalid syntax

Help me to understand why I made those two errors.

Upvotes: 0

Views: 42

Answers (3)

Sadegh_Ghaffarian
Sadegh_Ghaffarian

Reputation: 21

**First you miss ')' for sorted function and second you have whitespace on range function and you miss '()' for that **

def isAnagram(s,t):

    if len(s)!=len(t):        
        return False
    else:    
        list_t = sorted(list(set(t)))
        list_s = sorted(list(set(s)))
        if list_s != list_t:            
            return False
        else:
            i = 0
            j = []
            k = []
            for i in range(len(list_s)):
                j.append(list_s.count(list_s[i]))
                k.append(list_t.count(list_t[i]))
                i=i+1
                if j!=k:
                    return False
                else:                      
                      return True

Upvotes: 0

readyplayer77
readyplayer77

Reputation: 2159

You're missing parentheses in your code:

  • You did not close the parentheses for sorted- it should be list_t = sorted(list(set(t))) As @Dan D. mentioned, your program is looking for a closing parentheses. When it got another letter instead, it returns a series of syntax errors
  • range is a function, so you need for i in range (len(list_s)):

This code should compile correctly:

def isAnagram(s,t):  
    if len(s)!=len(t):        
        return False
    else:    
        list_t = sorted(list(set(t))) # add missing parenthesis
        list_s = sorted(list(set(s))) # add missing parenthesis
        if list_s != list_t:            
            return False
        else:
            i=0
            j=[]
            k=[]
            for i in range(len(list_s)): # add missing parenthesis
                j.append(list_s.count(list_s[i]))
                k.append(list_t.count(list_t[i]))
                i=i+1
                if j!=k:
                    return False
                else:                      
                    return True

Upvotes: 0

Dan D.
Dan D.

Reputation: 74645

Your code is basically:

(1

The parser is looking for ) and doesn't find it and instead reports a number of different errors depending on what it finds instead.

Upvotes: 1

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