CODEWITHSUNDEEP
pythonregexstring
Wahab Aftab
Wahab Aftab

Reputation: 59

Regex for numbers including decimal and slashes

I have a string like this:

"8 R-301 288/313 0.24 TT-2079 347.48"

Now I want to extract 288/313 and 0.24 using regex So I wrote this:

r42=re.findall(r"8 +R-301.*",pdf[i])
if len(r42[0].split())>3:
  print(r42[0].split())
  logbook['R-301 Temp']=r42[0].split()[2]
  logbook['R-301 P']=r42[0].split()[3]

So in an ideal case number comes in 2nd and 3rd index and I can get it.

But the problem I'm facing is that sometimes 288/313 has spaces like this 288 / 313, also the second number 0.24 can have a slash too so it can be like 0.24/0.25 or 0.24 /0.25. So the above regex doesn't work.

What would be an ideal regex for these decimal slash numbers with random spaces?

Note: The string can have multiple spaces between characters.

Edit:

Sorry I forgot one detail here:

numbers can have - like in the above example it can be -/313 instead of 288/313 or - instead of 0.24 or 0.24/- or -/0.24.

Something like this:

"8 R-301 288/- - TT-2079 347.48"

I want to target those cases as well.

Upvotes: 3

Views: 209

Answers (3)

RavinderSingh13
RavinderSingh13

Reputation: 133508

With your shown samples, could you please try following regex.

Let's say following are the values:

var="""8 R-301 288/313 0.24/0.25 TT-2079 347.48
8 R-301 288 / 313 0.24/0.25 TT-2079 347.48
8 R-301 288 / 313 0.24 / 0.25 TT-2079 347.48
8 R-301 - / 313 -/ 0.25 TT-2079 347.48
8 R-301 288 /313 -/ 0.25 TT-2079 347.48
8 R-301 313 / - -/ 0.25 TT-2079 347.48
8 R-301 288 / 313 0.24/ 0.25 TT-2079 347.48
8 R-301 123/313 -/12123 TT-2079 347.48
8 R-301 123.12/31.23 -/12123 TT-2079 347.48
8 R-301 123/313 -/- TT-2079 347.48
8 R-301 123 12123 TT-2079 347.48
8 R-301 -/123 -/- TT-2079 347.48"""

Now following is the code:

import re
val = re.findall(r'^\d+\s+R-\d+\s+(.*?)T.*',var,re.M)
for i in val:
   re.findall(r'((?:\d+(?:\.\d+)?|-)(?:(?:\s+)?\/(?:\s+)?(?:\d+(?:\.\d+)?|-))?)',i,re.M)

Output will be as follows:

['288/313', '0.24/0.25']
['288 / 313', '0.24/0.25']
['288 / 313', '0.24 / 0.25']
['- / 313', '-/ 0.25']
['288 /313', '-/ 0.25']
['313 / -', '-/ 0.25']
['288 / 313', '0.24/ 0.25']
['123/313', '-/12123']
['123.12/31.23', '-/12123']
['123/313', '-/-']
['123', '12123']
['-/123', '-/-']

Explanation: Adding detailed explanation for above regex:

(                               ##Creating 1st capturing group here.
 (?:\d+(?:\.\d+)?|-)            ##In a non-capturing group matching digits with optional dot digits OR followed by - here.
 (?:(?:\s+)?\/                  ##In a non-capturing group with optional spaces with / here.
 (?:\s+)?(?:\d+(?:\.\d+)?|-))?  ##Matching optional spaces with digits and optional digits OR with optional - here.
)                               ##Closing 1st capturing group here.

Upvotes: 4

Andrej Kesely
Andrej Kesely

Reputation: 195438

Try:

import re

tests = [
    "8    R-301            288/313        0.24     TT-2079            347.48",
    "8    R-301            288 / 313        0.24     TT-2079            347.48",
    "8    R-301            288/313        0.24/0.25     TT-2079            347.48",
    "8    R-301            288/313        0.24/ 0.25     TT-2079            347.48",
    "8    R-301            288 / 313        0.24 / 0.25     TT-2079            347.48",
    "8    R-301            288/-        -     TT-2079            347.48",
    "8    R-301            288/-        0.1 /-     TT-2079            347.48",
    "8    R-301            -/233       -     TT-2079            347.48",
    "8 R-301 313 -/12123 TT-2079 347.48",
]

r = re.compile(
    r"\s+((?:[\d\.-]+\s*/\s*[\d\.-]+)|[\d\.-]+)\s+([\d\.-]+(?:\s*/\s*[\d\.-]+)?)"
)

for test in tests:
    m = r.search(test)
    if m:
        m = m.groups()
        number1 = m[0].replace(" ", "")
        number2 = m[1].replace(" ", "")
        print(number1, number2)

Prints:

288/313 0.24
288/313 0.24
288/313 0.24/0.25
288/313 0.24/0.25
288/313 0.24/0.25
288/- -
288/- 0.1/-
-/233 -
313 -/12123

EDIT: Updated regex to accept - EDIT2: Updated regex to accept first value without slash /

Upvotes: 3

Jan
Jan

Reputation: 43169

I think it is far easier to split on more than two spaces and use the corresponding parts afterwards:

import re

tests = [
    "8    R-301            288/313        0.24     TT-2079            347.48",
    "8    R-301            288 / 313        0.24     TT-2079            347.48",
    "8    R-301            288/313        0.24/0.25     TT-2079            347.48",
    "8    R-301            288/313        0.24/ 0.25     TT-2079            347.48",
    "8    R-301            288 / 313        0.24 / 0.25     TT-2079            347.48",
    "8    R-301            288/-        -     TT-2079            347.48",
    "8    R-301            288/-        0.1 /-     TT-2079            347.48",
    "8    R-301            -/233       -     TT-2079            347.48",
]

rx = re.compile(r'\s{2,}')

for line in tests:
    parts = rx.split(line)
    print(parts[2])
    print(parts[3])

Which yields

288/313
0.24
288 / 313
0.24
288/313
0.24/0.25
288/313
0.24/ 0.25
288 / 313
0.24 / 0.25
288/-
-
288/-
0.1 /-
-/233
-

Upvotes: 2

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