CODEWITHSUNDEEP
python
Waqar Rafique
Waqar Rafique

Reputation: 39

Need to print the most frequent lenght of 5,s and 6,s in dice rolls

I actually have three task out of which two has been completed now I am really stuck with the last one.

  1. Check two consecutive 66 (Working)
  2. Longest sequence of rolls with 6 (Working)
  3. Want to check the number for most frequent length of 5's and 6's. For example in 5533661656 the 656 is the longest but there is only one series of length three but answer should be 2 as 55, 66 are there. Similarly 456116513656124566 have length of 2 and 3 which are occuring twice. Now program should print the longest length and answer should be 3

here is code


trial = int(randint(1, 500))
print(trial)
result = ''
for i in range(trial):
    init_num = str(randint(1, 6))
    result += init_num
print(result)


def double_six(result):
    last_dice = '0'
    counter = 0
    for i in range(trial):
        if result[i] == '6' and last_dice == '6':
            counter += 1
            last_dice = '0'
        else:
            last_dice = result[i]
    return counter
print(double_six(result))

def no_six(result):
    s = str(result).split('6')
    l = 0
    for i in s:
        if l < len(i):
            l = len(i)
        if len(i) > l:
            l = i
    return (l)
print(no_six(result))
#
# def lucky_series(result)

Upvotes: 1

Views: 85

Answers (1)

rEsonansDx
rEsonansDx

Reputation: 35

This can probably be simplified with regex but I don't know how to:
Here's my solution

result = str(322226555453442214634442111625423563466312534536531251541656625421252464254536351661534211622365625514522561513611151366313122241413512123614521)

Replace the numbers 1 to 4 with spaces then split it to turn it into a list.

result = result.replace('1',' ').replace('2',' ').replace('3',' ').replace('4',' ').split()  
#['6555', '5', '6', '6', '5', '56', '66', '5', '5', '65', '5', '5', '6566', '5', '5', '6', '5', '5', '6', '5', '66', '5', '6', '656', '55', '5', '56', '5', '6', '5', '66', '5', '6', '5']

then find the length of each 5-6 item in that list then store them into another list:

lengths = [len(a) for a in result] #list-comprehension
#[4, 1, 1, 1, 1, 2, 2, 1, 1, 2, 1, 1, 4, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 3, 2, 1, 2, 1, 1, 1, 2, 1, 1, 1]

Count the similar length items using list.count starting from 2 together with their frequency

total = [[i , lengths.count(i)] for i in range(1000)[2:] if lengths.count(i) != 0]
#[[2, 7], [3, 1], [4, 2]]

then use max() to find the length with the highest frequency(get max based on second item)

max(total, key = lambda x: x[1])
#[2, 7]

Function:

def most56(result):
    result = result.replace('1',' ').replace('2',' ').replace('3',' ').replace('4',' ').split()
    lengths = [len(a) for a in result]
    total = [ [i, lengths.count(i)] for i in range(1000)[2:] if lengths.count(i) != 0]
    if total:
        most = max(total, key = lambda x: x[1])
        return most[0]
    return 'no long numbers'

Upvotes: 1

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