CODEWITHSUNDEEP
pythonclassuser-interfacetkinterpython-class
Anmol
Anmol

Reputation: 45

Accessing entry field value of one tkinter class in another

I have just started learning tkinter and came across a problem.I have two tkinter classes. I am entering a value in an entry field of one tkinter class and trying to show it in the label in the other class. I have tried it many ways but not able to do this. Please if anyone can help me in doing so. Here is my code.

import tkinter
from tkinter import Tk, Toplevel
from tkinter import *


def main():
    main_window = Tk()
    app = first(main_window)
    main_window.mainloop()


class first:
    def __init__(self, root):
        self.root = root
        self.root.title('First window')
        self.root.geometry('1350x700+0+0')

        single_id = Label(self.root, text="Enter id", font=("Times New Roman", 14), bg='white',
                          fg='black')
        single_id.place(x=200, y=200)

        self.mystring = tkinter.StringVar(self.root)

        self.txt_id = Entry(self.root, textvariable=self.mystring, font=("Times New Roman", 14), bg='white')
        self.txt_id.place(x=300, y=200, width=280)
        btn_search = Button(self.root, command=self.second_window, font=("Times New Roman", 15, 'bold'), text='Get Id')
        btn_search.place(x=300, y=400, width=220, height=35)

    def second_window(self):
        self.root.destroy()
        main_window = Tk()
        app = second(main_window)
        main_window.mainloop()

    def return_id(self):
        return self.mystring.get()


class second:
    def __init__(self, root):
        self.root = root
        self.root.title('Second window')
        self.root.geometry('1350x700+0+0')
        id = first.return_id

        get_id = Label(self.root, text=id, font=("Times New Roman", 14), bg='white',
                       fg='black')
        get_id.place(x=200, y=350)


if __name__ == '__main__':
    main()

The way I am doing it is not showing the actual value. Instead it gives 2064283946496return_id

Any help would be greatly appreciated.

Upvotes: 1

Views: 889

Answers (1)

typedecker
typedecker

Reputation: 1390

What you can do is pass the first class object as an argument to the second class intializer and then call the method on it. Something like this seems to work -:

import tkinter
from tkinter import Tk, Toplevel
from tkinter import *


def main():
    main_window = Tk()
    app = first(main_window)
    main_window.mainloop()


class first:
    def __init__(self, root):
        self.root = root
        self.root.title('First window')
        self.root.geometry('1350x700+0+0')

        single_id = Label(self.root, text="Enter id", font=("Times New Roman", 14), bg='white',
                          fg='black')
        single_id.place(x=200, y=200)

        self.mystring = tkinter.StringVar(self.root)

        self.txt_id = Entry(self.root, textvariable=self.mystring, font=("Times New Roman", 14), bg='white')
        self.txt_id.place(x=300, y=200, width=280)
        btn_search = Button(self.root, command=self.second_window, font=("Times New Roman", 15, 'bold'), text='Get Id')
        btn_search.place(x=300, y=400, width=220, height=35)

    def second_window(self):
        self.root.destroy()
        main_window = Tk()
        app = second(main_window, self)
        main_window.mainloop()

    def return_id(self):
        return self.mystring.get()


class second:
    def __init__(self, root, first):
        self.root = root
        self.root.title('Second window')
        self.root.geometry('1350x700+0+0')
        id = first.return_id()

        get_id = Label(self.root, text=id, font=("Times New Roman", 14), bg='white',
                       fg='black')
        get_id.place(x=200, y=350)


if __name__ == '__main__':
    main()

Upvotes: 2

Related Questions