CODEWITHSUNDEEP
pythondictionary
madil26
madil26

Reputation: 95

highest value in dictionary

What I would like to do is loop through my_family and return the member with the highest Age.

my_family = {
    "member1": {"Name":"Person1","Gender": "Male","Age": 24},
    "member2": {"Name":"Person2","Gender": "Male","Age": 32},
    "member3": {"Name":"Person3","Gender": "Female","Age": 62}
}

My attempt is below:

k = my_family.keys()  
v = my_family.values()

def highAge():
    for k,v in my_family.items():
        if "Age" in my_family.items():
            print("Age found")
    else:
         print("Failed")

highAge()

The current output is Failed.

Upvotes: 0

Views: 58

Answers (3)

Valérie Gelbgras
Valérie Gelbgras

Reputation: 53

You can also sort your dictionary by the age and take the last item

my_family = {
    "member1": {"Name":"Person1","Gender": "Male","Age": 24},
    "member3": {"Name":"Person3","Gender": "Female","Age": 62},
    "member2": {"Name":"Person2","Gender": "Male","Age": 32},
}

my_family_sorted_by_age = sorted(my_family.items(), key=lambda item: item[1]["Age"])
print(my_family_sorted_by_age[-1])

Upvotes: 0

Nirmal Dey
Nirmal Dey

Reputation: 189

If you don't care about keys then here is a simple solution to your problem.

my_family = {
    "member1": {"Name":"Person1","Gender": "Male","Age": 24},
    "member2": {"Name":"Person2","Gender": "Male","Age": 32},
    "member3": {"Name":"Person3","Gender": "Female","Age": 62}
}

person_with_max_age = max(my_family.values(), key=lambda f: f["Age"])

print(person_with_max_age)

>> {'Name': 'Person3', 'Gender': 'Female', 'Age': 62}

Upvotes: 2

MarianD
MarianD

Reputation: 14201

The quick fix:

Your first 2 lines are superfluous, delete them:

k = my_family.keys()  
v = my_family.values()

Then in the if statement change my_family.items() to v, and append the break command. So your full program will be

def highAge():
    for k, v in my_family.items():
        if "Age" in v:
            print("Age found")
            break
    else:
         print("Failed")

highAge()

Upvotes: 1

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