Reputation: 79
I'm newbie to R and have a data frame with 25k rows and would like to group the sum of "Freq"
inputs within a range of "Var1"
(let's say from 5 to 5).
Idea is to have less rows and create a histogram.
Here are 20 rows for simplicity:
Var1 <- c(0:19)
Freq <- c(289, 370, 2295, 2691, 2206, 1624, 1267, 1076, 971, 889, 891, 834, 866, 780, 794, 809, 772, 740, 742, 734)
df <- data.frame(Var1, Freq)
Here is what I would expect:
Var1_intervals <- c("0 - 4", "5 - 9", "10 - 14", "15-19")
Freq_sum <- c(7851, 5837, 4165, 3797)
df_2 <- data.frame(Var1_intervals, Freq_sum)
Upvotes: 4
Views: 353
Reputation: 78917
Make ID column for your interval (in this case 5), then group and summarise
library(dplyr)
df %>%
mutate(Intervals_by5 = rep(row_number(), each=5, length.out = n())) %>%
group_by(Intervals_by5) %>%
summarise(Freq_sum = sum(Freq))
Output:
Intervals_by5 Freq_sum
<int> <dbl>
1 1 7851
2 2 5827
3 3 4165
4 4 3797
Upvotes: 4
Reputation: 886998
An option with data.table
library(data.table)
setDT(df)[, .(n = sum(Freq)), by = .(Group = findInterval(Var1, (0:4) * 5))]
Upvotes: 3
Reputation: 474
And another solution using dplyr
:
df %>%
group_by(cut(Var1, (0:4)*5, right = FALSE)) %>%
summarise(n = sum(Freq))
Upvotes: 4
Reputation: 101159
Here is another base R option using tapply
with(
df,
data.frame(
Var1 = tapply(Var1,ceiling(seq_along(Var1)/5),function(x) paste0(range(x),collapse = "-")),
Freq = tapply(Freq,ceiling(seq_along(Freq)/5),sum)
)
)
which gives
Var1 Freq
1 0-4 7851
2 5-9 5827
3 10-14 4165
4 15-19 3797
Upvotes: 3
Reputation: 39647
You can use aggregate
and cut
to sum up per interval.
aggregate(df["Freq"], list(cut(df$Var1, (0:4)*5, right = FALSE)), sum)
# Group.1 Freq
#1 [0,5) 7851
#2 [5,10) 5827
#3 [10,15) 4165
#4 [15,20) 3797
Upvotes: 4