Reputation:
This is my third project in Python. I'm working on a calculator, and I have all the operations etc., working just fine. However, I would like to allow the user to not have to input a second number on two of the operations ( that being Euler's number and Pi) and for the calculator to still work. For instance, if I would like to multiply a number by pi, right now, I would need to input '1' as the second number. I want to eliminate this need. I really appreciate any help you can provide.
import math
def welcome():
print('''
Welcome to Calculator
''')
# Define our function
welcome()
def calculate():
operation = input('''
Please type in the math operation you would like to complete:
+ for addition
- for subtraction
* for multiplication
/ for division
** for power
% for modulo
pi to multiply by Pi
e to multiply by Euler's Number
''')
number_1 = float(input('Please enter the first number: '))
number_2 = float(input('Please enter the second number: '))
if operation == 'e':
print('{} * e = '.format(number_1, math.e))
print(number_1 * math.e)
elif operation == 'pi':
print('{} * Pi = '.format(number_1, math.pi))
print(number_1 * math.pi)
elif operation == '+':
print('{} + {} = '.format(number_1, number_2))
print(number_1 + number_2)
elif operation == '-':
print('{} - {} = '.format(number_1, number_2))
print(number_1 - number_2)
elif operation == '*':
print('{} * {} = '.format(number_1, number_2))
print(number_1 * number_2)
elif operation == '/':
print('{} / {} = '.format(number_1, number_2))
print(number_1 / number_2)
elif operation == '**':
print('{} ** {} ='.format(number_1, number_2))
print(number_1 ** number_2)
elif operation == '%':
print('{} % {} ='.format(number_1, number_2))
print(number_1 % number_2)
else:
print('You have not typed a invalid operator, please run the program again.')
# Add again() function to calculate() function
again()
def again():
calc_again = input('''
Do you want to calculate again?
Please type Y for YES or N for NO.
''')
if calc_again.upper() == 'Y':
calculate()
elif calc_again.upper() == 'N':
print("Thank you for using the calculator. I'll be here whenever you need me.")
else:
again()
# Call calculate() outside of the function
calculate()
Upvotes: 1
Views: 197
Reputation: 175
You could solve this problem without too many changes to your code by moving the input for the second number into all the loops after your conditional checks for e and pi.
As an example:
number_1 = float(input('Please enter the first number: '))
if operation == 'e':
print('{} * e = '.format(number_1, math.e))
print(number_1 * math.e)
elif operation == 'pi':
print('{} * Pi = '.format(number_1, math.pi))
print(number_1 * math.pi)
elif operation == '+':
number_2 = float(input('Please enter the second number: '))
print('{} + {} = '.format(number_1, number_2))
print(number_1 + number_2)
This doesn't follow best practices, but it should get done what you want. If you want a better way to do it than this, I can edit this answer to include the improvements and why they are better.
Upvotes: 0
Reputation: 2737
Zeroing in on the specific fragment you would need to change, here is one way to do it:
...
number_1 = float(input('Please enter a number: '))
if operation == 'e' or operation == 'pi':
if operation == 'e':
print('{} * e = '.format(number_1, math.e))
print(number_1 * math.e)
elif operation == 'pi':
print('{} * Pi = '.format(number_1, math.pi))
print(number_1 * math.pi)
else:
number_2 = float(input('Please enter a second number: '))
if operation == '+':
print('{} + {} = '.format(number_1, number_2))
print(number_1 + number_2)
elif operation == '-':
print('{} - {} = '.format(number_1, number_2))
print(number_1 - number_2)
...
Upvotes: 1
Reputation: 680
Just add an if condition above
number_2 = float(input('Please enter the second number: '))
Like this
if(operation != 'e' || operation != 'pi'):
number_2 = float(input('Please enter the second number: '))
Upvotes: 1