CODEWITHSUNDEEP
pythoninteger
Eliott Reed
Eliott Reed

Reputation: 321

How to use a number in a list as a bench mark for comparison

I have written some code but would like to make it more simple.

How can I extract the desired integer from my list without all the extra lines of code which turn it into an integer so I can use it in my if statement?

def nextRound(k,scores):
    count = 0
    integers = scores[k-1:k]
    strings = [str(integer) for integer in integers]
    a_string = "".join(strings)
    an_integer = int(a_string)
    for i in scores:
        if i > 0 and i >= an_integer:
            count += 1
    return count

print(nextRound(2,[1,1,1,1]))

here are the instructions for the question:

“If a contestant earns a score equal to or greater than the k-th place finisher, they will advance to the next round if their own score is greater than 0”. So write a function nextRound(k,scores) which will count how many contestants will progress to the next round.

Upvotes: 0

Views: 80

Answers (1)

TomM
TomM

Reputation: 175

This accomplishes the same thing, I think you may be overthinking it by confusing a list of ints as also having the datatype list for its members:

def nextRound(k,scores):
    count = 0
    integer = scores[k]
    for i in scores:
        if i > 0 and i >= integer:
            count += 1
    return count

print(nextRound(2,[1,1,1,1]))

Running this gives the expected output of 4. This does assume that the scores are given presorted.

Upvotes: 1

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