CODEWITHSUNDEEP
bashshell
Dmytro
Dmytro

Reputation: 15

Get word from last executed bash command

I have a script with something like this:

git clone ssh://anothersite.com /home/user/another_directory

I need to check if the command has worked, and only then proceed to the next commands. I solved it in a similar way:

if [ "$?" -ne 0 ]; then
echo "{$2} command failed.";
exit 1

I need the word "clone" or another word that will be encountered further in the script instead of {$ 2}. If I substitute $ 0, then it gives me the name of the script that I ran, and not the command "git clone" as I expect

Upvotes: 1

Views: 59

Answers (2)

Zilog80
Zilog80

Reputation: 2562

You can use shell functions to achieve that. Here is an example implementation with the function my_git_function that will display an error message:

# Process git operation
# Parameters : my_git_function [ git_operation [ operation_arguments ] ]
# Return : git exit status code, 0 if NOP or success
my_git_function() {
  if [ $# = 0 ]; then
    return 0
  fi
  local git_operation="$1"
  shift
  if git "$git_operation" "$@"; then
    return 0
  else
    local exit_code="$?"
    echo "Command $git_operation failed with exit code $exit_code." >&2
    return "$exit_code"
  fi
}
# Example with clone
if ! my_git_function clone ssh://anothersite.com /home/user/another_directory
  # Failed command, error message already displayed
fi

Upvotes: 3

KamilCuk
KamilCuk

Reputation: 140970

I need to check if the command has worked

Check with an if.

if ! git clone ssh://anothersite.com /home/user/another_directory; then
   echo "Clone failed" >&2
   exit 1
fi

I need the word "clone" or another word that will be encountered further in the script instead of {$ 2}

Write a handy wrapper function and pass command to execute as arguments.

failon() {
    if ! "$@"; do
       echo "Command failed: $*" >&2
       exit 1
    fi
}
failon git clone ssh://anothersite.com /home/user/another_directory

Upvotes: 4

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