CODEWITHSUNDEEP
regex
monte
monte

Reputation: 1885

regex extract word group before the end of line

I have following samples of strings

commit: February 2021 Master DS Commit c285fcbf59b698ec5695d35989a420da7659
commit: March market Sales Volume PFJan2021
commit: August market Input PFJan2021
commit: February 2021 Master DS Commit c5695d359820da7659

I want to extract words which are in between commit: and Commit c285cb... or the end of line. The result is as follows:

February 2021 Master DS
March market Sales Volume PFJan2021
August market Input PFJan2021
February 2021 Master DS

I understand that using following regex, I can extract words after commit:

.*commit: (.*)

I have tried another regex: .*commit: (.*)Commit.* but it returns blank where Commit word doesn't exist (I believe that's the expected behaviour).

Is there a way to use some style of or condition which checks if Commit word exists return words before it and after commit:?

Upvotes: 1

Views: 97

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627370

You can use

commit:\s*(.*?)(?:\s*Commit\b|$)

See the regex demo.

Details:

  • commit: - a literal string
  • \s* - zero or more whitespaces
  • (.*?) - Group 1: any zero or more chars other than line break chars as few as possible
  • (?:\s*Commit\b|$) - either zero or more whitespaces and Commit as a whole word or end of string.

Upvotes: 2

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