CODEWITHSUNDEEP
java
JcDav
JcDav

Reputation: 21

Incompatible Types - found:int required:boolean

I'm trying to display: EQUIVALENT if the first numerical input is equal to the second input. What's wrong with my code?

import java.io.*;
public class TwoNum{
    public static void main(String[] args){
        int number;
        int number2;
        String input1="";
        String input2="";

        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));

        System.out.println("Input a number: ");

        try{
            input1=in.readLine();
        }catch(IOException e){
            System.out.println("Error!");
        }

        number = Integer.parseInt(input1);

        try{
            input2=in.readLine();
        }catch(IOException e){
            System.out.println("Error!");
        }

        number2 = Integer.parseInt(input2);

        if(number=number2)
        {
            System.out.println("EQUIVALENT");
        }
        if(number>number2)
        {
            System.out.println("GREATER THAN");
        }
    }
}

Upvotes: 2

Views: 18764

Answers (3)

Harry Joy
Harry Joy

Reputation: 59694

Your first condition should be:

if(number==number2)

In if condition use == to compare 2 integers. Also don't use if in both condition use else if(). Using if in both will check condition for both even though first condition is true it will check for second condition and you are missing 3rd condition for LESS THAN.

Upvotes: 1

Ray Toal
Ray Toal

Reputation: 88478

The expression number=number2 is an assignment expression producing an integer. But a boolean is expected in this context. You want == instead of =. Common mistake.

Upvotes: 2

Mark Peters
Mark Peters

Reputation: 81164

Use 

 if(number==number2)

Instead of 

 if(number=number2)

The first compares number2 to number and if they are equal evaluates to true. The second assigns the value of number2 to the variable number and the expression evaluates to number/number2, an int.

Link

Upvotes: 10

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