Prolem in replacing special characters "@" with a blank using regex replace function

Question

i am using following regex expression to replace

query=query.replace(/[^a-zA-Z 0-9*?:.+-^""_]+/g,'')

But when my query is diam!@#%d i get diam@d after execution of this. it means it is not replacing @ . Why is so ??

Answer 1

You need to escape - sign in your regex (- => \-), i.e.: [^a-zA-Z 0-9*?:.+\-^""_]+, therefore it will match: !@#%.