CODEWITHSUNDEEP
pythondatetimetimezonezoneinfo
guyguyguy12345
guyguyguy12345

Reputation: 571

Datetime with timezone

As far as I understood ZoneInfo in python 3.9 fixes the issue of "The year of 2038" problem with DST time issue. But I can see that the timedelta is wrong. Below it should have been 2 hours, not 3. What is wrong?

from zoneinfo  import ZoneInfo
import datetime
dt = datetime.datetime(2038,3,14,0,0, tzinfo = ZoneInfo(r'America/New_York'))
print(dt)           
dt2 = datetime.datetime(2038,3,14,3,0, tzinfo = ZoneInfo(r'America/New_York'))
print(dt2-dt)

Upvotes: 0

Views: 219

Answers (2)

kayuapi_my
kayuapi_my

Reputation: 508

from zoneinfo  import ZoneInfo
import datetime
dt = datetime.datetime(2038,3,14,0,0, tzinfo = ZoneInfo(r'America/New_York'))
print(dt)           # Output: 2038-03-14 00:00:00-05:00
dt2 = datetime.datetime(2038,3,14,3,0, tzinfo = ZoneInfo(r'America/New_York'))
print(dt2)          # Output: 2038-03-14 03:00:00-04:00
timedelta = dt2-dt1
print(timedelta)    # Output: 3:00:00

The above is correct because it is made aware of the DST, aka in the DST aware context. For example, if you add 3 hours to 2038-03-14 00:00:00-05:00 like the code below, you get a consistent result:

from zoneinfo  import ZoneInfo
import datetime
dt = datetime.datetime(2038,3,14,0,0, tzinfo = ZoneInfo(r'America/New_York'))
print(dt)                                      # Output: 2038-03-14 00:00:00-05:00
print(dt+datetime.timedelta(hours=3))          # Output: 2038-03-14 03:00:00-04:00

However, your thinking of 2 hours time difference is correct in the NO-DST-AWARE context, as shown below:

from zoneinfo  import ZoneInfo
import datetime
dt = datetime.datetime(2038,3,14,0,0, tzinfo = ZoneInfo(r'America/New_York'))
print(dt)           # Output: 2038-03-14 00:00:00-05:00
dt2 = datetime.datetime(2038,3,14,3,0, tzinfo = ZoneInfo(r'America/New_York'))
print(dt2)          # Output: 2038-03-14 03:00:00-04:00
dt_isoformat = dt.isoformat() 
print(dt_isoformat) # Output: 2038-03-14T00:00:00-05:00
dt2_isoformat = dt2.isoformat() 
print(dt2_isoformat) # Output: 2038-03-14T03:00:00-04:00
print(datetime.datetime.fromisoformat(dt2_isoformat)-datetime.datetime.fromisoformat(dt_isoformat)) # Output: 2:00:00

Upvotes: 1

Otaku Gate
Otaku Gate

Reputation: 1

I think It’s 3 hours, from 00 (which is 12) to 3 that’s absolutely 3 hours.

Upvotes: 0

Related Questions