CODEWITHSUNDEEP
c#asp.net-mvcasp.net-corejsonserializer
jubi
jubi

Reputation: 625

deserialize json into my C# object gives error

I get such JSON and want to deserialize it into my C# object. But this ends up in an error that cannot deserialize. Can I get help in fixing this?

 public class UserDto {
   public string Id { get; set; }
   public string Name { get; set; }
   public List<string> Permissions { get; set; }
 }

Above is the model object for binding the API output

HttpResponseMessage response = await client.GetAsync($"/users");
if (!response.IsSuccessStatusCode || response.Content == null) {
  return null;
}
string result = await response.Content.ReadAsStringAsync();

UserDto users = await response.Content.ReadAsJsonAsync<UserDto>();

List<UserDto> x2 = JsonConvert.DeserializeObject<List<UserDto>>(result);

The above getasync method gives me the below result and i am trying to deserialize it to object.

{
    "users": [{
        "id": "1",
        "name": "ttest",
        "permissions": [
            "add",
            "edit",
            "delete"
        ]
    }]
}

Error:

Cannot deserialize the current JSON object (e.g. {"name":"value"}) 
into type 'System.Collections.Generic.List`1[****.Models.UserDto]' 
because the type requires a JSON array (e.g. [1,2,3]) to deserialize correctly.

To fix this error either change the JSON to a JSON array (e.g. [1,2,3]) 
or change the deserialized type so that it is a normal .NET type 
(e.g. not a primitive type like integer, not a collection type like an
array or List<T>) that can be deserialized from a JSON object.
JsonObjectAttribute can also be added to the type to force it to 
deserialize from a JSON object.

I get such JSON and want to deserialize it into my C# object. But this ends up in an error that cannot deserialize. Can I get help in fixing this?

Upvotes: 0

Views: 1864

Answers (1)

Prasad Telkikar
Prasad Telkikar

Reputation: 16049

In your JSON, Users JArray is inside a JObject, so to convert your JSON string you need List<User> inside a RootObject class like,

public class User
{
    public string id { get; set; }
    public string name { get; set; }
    public List<string> permissions { get; set; }
}

public class Root
{
    public List<User> users { get; set; }
}

Deserialize like,

Root myDeserializedClass = JsonConvert.DeserializeObject<Root>(result);

.NETFIDDLE

Upvotes: 1

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