CODEWITHSUNDEEP
c#methodscodedomconsole.writeline
user725913
user725913

Reputation:

C# CodeDom Console.WriteLine + MethodReference

I am attempting to create a Console.WriteLine statement (shown below) using CodeDom. This is giving me mainly because of the Environment.NewLine call - I can't figure out the proper way of embedding a method within the Console.WriteLine call. I will show you the code I am trying to produce along with the code that I am using. Perhaps someone will be able to catch, and correct my error.

The code I would like to produce:

Console.WriteLine("Error reading from source: " + Environment.NewLine + "Error code: " + ex.Message);

The code that I am using:

const char quote = '\u0022'; // Represents a " mark
CodeMethodInvokeExpression invoke = new CodeMethodInvokeExpression(
new CodeTypeReferenceExpression("Console"), "WriteLine",
new CodeExpression[] {
new CodeVariableReferenceExpression(quote + "Error reading from source: " + quote + " + "),
new CodeFieldReferenceExpression("Environment"), "NewLine"),
new CodeVariableReferenceExpression("+ " + quote + "Error code: " + quote + " + " + "ex" + ".Message")})));

The code that is being generated:

Console.WriteLine("Error reading source: " + , Environment.NewLine, + "Error code: " + ex.Message);

Because I am using MethodInvoke, CodeDom is separating each line by a ", " as if they were each new parameters within the same method... How can I go about this the proper way?

Upvotes: 0

Views: 982

Answers (2)

svick
svick

Reputation: 244848

You have to write the CodeDOM the same way you write the code normally. That is, when you want to call a method with one argument, you have to give it one argument.

Also, if you want to have a constant in the generated code, the proper way is to use CodePrimitiveExpression. You are trying to creating a variable with the name "Error reading from source: ".

Because constructing the whole expression by hand would be tedious and unreadable, you could create a helper method for joining multiple expressions using the same operator:

static CodeExpression Join(
    CodeBinaryOperatorType op, params CodeExpression[] expressions)
{
    return expressions.Aggregate((l, r) => new CodeBinaryOperatorExpression(l, op, r));
}

Using that, you can now write:

new CodeMethodInvokeExpression(
    new CodeTypeReferenceExpression(typeof(Console)), "WriteLine",
    Join(CodeBinaryOperatorType.Add,
            new CodePrimitiveExpression("Error reading from source: "),
            new CodePropertyReferenceExpression(
                new CodeTypeReferenceExpression(typeof(Environment)),
                "NewLine"),
            new CodePrimitiveExpression("Error code: "),
            new CodePropertyReferenceExpression(
                new CodeVariableReferenceExpression("ex"), "Message")));

Which produces the following code:

System.Console.WriteLine(((("Error reading from source: " + System.Environment.NewLine)
                + "Error code: ")
                + ex.Message))

Of course, you can always use snippets:

new CodeMethodInvokeExpression(
    new CodeTypeReferenceExpression(typeof(Console)), "WriteLine",
    new CodeSnippetExpression(
        "\"Error reading from source: \" + Environment.NewLine + \"Error code: \" + ex.Message"));

Also, using the formatting overload of Console.WriteLine() might be better.

Upvotes: 1

VVS
VVS

Reputation: 19602

Use the Console.WriteLine(String, Object[]) overload and do the equivalent to

Console.WriteLine("Error reading from source: {0} Error code: {1}", 
    Environment.NewLine, 
    ex.Message);

in CodeDom.

Upvotes: 0

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