Reputation: 765
I am trying to get a list of list of tuples : something like [ [(1,0),(2,0),(3,0)],[(1,1),(2,1),(3,1)....]]
I used this statement
set([(a,b)for a in range(3)]for b in range(3))
But it gives me an error
TypeError: unhashable type: 'list'
I have 2 questions for the Python Guru's:
a) When I look at the Python definition of Hashable -
"An object is hashable if it has a hash value which never changes during its lifetime (it needs a hash() method)"
when I used dir function on the expression above
dir([(a,b)for a in range(3)]for b in range(3))
it seems to say the __hash__
is there. So, why do I get the error?
I was able to get [[(0, 0), (1, 0), (2, 0)], [(0, 1), (1, 1), (2, 1)], [(0, 2), (1, 2), (2, 2)]]
by using the list command :
list(list((a,b) for a in range(3)) for bin range(3))
b)list and set both takes Iterable as parameter. How come one works(list) and another doesn't (set)?
Upvotes: 64
Views: 308702
Reputation: 27216
You are creating a set
via the set(...)
call, and set
needs hashable items. You can't have set of lists. Because lists aren't hashable.
[[(a,b) for a in range(3)] for b in range(3)]
is a list. It's not a hashable type. The __hash__
you saw in dir(...)
isn't a method, it's just None``.
A list comprehension returns a list, you don't need to explicitly use list there, just use:
>>> [[(a,b) for a in range(3)] for b in range(3)]
[[(0, 0), (1, 0), (2, 0)], [(0, 1), (1, 1), (2, 1)], [(0, 2), (1, 2), (2, 2)]]
Try those:
>>> a = {1, 2, 3}
>>> b= [1, 2, 3]
>>> type(a)
<class 'set'>
>>> type(b)
<class 'list'>
>>> {1, 2, []}
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unhashable type: 'list'
>>> print([].__hash__)
None
>>> [[],[],[]] #list of lists
[[], [], []]
>>> {[], [], []} #set of lists
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unhashable type: 'list'
Upvotes: 41
Reputation: 10888
Example:
>>> {1, 2, [3, 4]}
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unhashable type: 'list'
>>> {1, 2, (3, 4)}
set([1, 2, (3, 4)])
Note that hashing is somehow recursive and the above holds true for nested items:
>>> {1, 2, 3, (4, [2, 3])}
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unhashable type: 'list'
Dict keys also are hashable, so the above holds for dict keys too.
Upvotes: 26
Reputation: 9511
The real reason because set
does not work is the fact, that it uses the hash function to distinguish different values. This means that sets only allows hashable objects. Why a list is not hashable is already pointed out.
Upvotes: 9
Reputation: 1608
... and so you should do something like this:
set(tuple ((a,b) for a in range(3)) for b in range(3))
... and if needed convert back to list
Upvotes: 7
Reputation: 9163
You'll find that instances of list
do not provide a __hash__
--rather, that attribute of each list is actually None
(try print [].__hash__
). Thus, list
is unhashable.
The reason your code works with list
and not set
is because set
constructs a single set of items without duplicates, whereas a list can contain arbitrary data.
Upvotes: 2
Reputation: 308111
A list is unhashable because its contents can change over its lifetime. You can update an item contained in the list at any time.
A list doesn't use a hash for indexing, so it isn't restricted to hashable items.
Upvotes: 14