CODEWITHSUNDEEP
pythonlistfunctiondictionarymax
Muskan Chouhan
Muskan Chouhan

Reputation: 3

How to find min and max value from a list that is passed on to a function as argument? I want to find min and max of list but not getting the output

*#Function to find out maximum and minimum marks #From a list input, then passed as an argument into the function *

def marks(*args):
    print(args)
    print(max(args))
    print(min(args))

#marks input
mymarks = list(map(int,input("Enter the marks of all subjects: ").split()))
**#function call**
marks(mymarks)

Output:
Enter the marks of all subjects: 67 77 89 56 40
([67, 77, 89, 56, 40],)
[67, 77, 89, 56, 40]
[67, 77, 89, 56, 40]

Upvotes: 0

Views: 884

Answers (2)

schilli
schilli

Reputation: 1848

You are almost there, but you make the entering of mymarks more complicated than needed.

Instead of using *args, just use plain args. And instead of the map, just call split() on the input value. split already returns a list.

def marks(args):
    print(args)
    print(max(args))
    print(min(args))


# marks input
mymarks = input("Enter the marks of all subjects: ").split()
marks(mymarks)

Upvotes: 0

Reshab Das
Reshab Das

Reputation: 170

Instead of using *args declare a variable like def marks(m) or use args[0].

Declaring variable will be the best as you can then just use max(m) to get the max value in list.

Your function sets max of args which is a tuple. Your list is inside that tuple.

Happy coding.

Upvotes: 1

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