CODEWITHSUNDEEP
ansible
stminion001
stminion001

Reputation: 353

Ansible, how to chain regex_replace statements?

I have a date that comes in like this 2023-05-10T21:12:42+00:00. To get rid of the +00:00 I do this:

vars:
    date1: " {{ item.expires | regex_replace('\\+00:00') }}"

However, when I print date1 it prints out "DATE1::: 2023-05-10T21:05:26" with a space before 2023. I then have to do another regex_replace on the date1 variable to get rid of the space in the beginning and assign it to a new variable like this:

date2: "{{ date1 | regex_replace(' ') }}"

I wanted to chain the regex_replace together like this but it didn't work:

date1: " {{ item.expires | regex_replace('\\+00:00') | regex_replace(' ') }}"

Is there a better way to do this?

Upvotes: 0

Views: 207

Answers (1)

P....
P....

Reputation: 18351

You are getting extra space because of extra space after the starting double quotes, double quotes preserve the starting space with it.

 date1: " {{ item.expires | regex_replace('\\+00:00') }}"
         ^
         ^
         ^

Change this to the following and you will get rid of starting space :

 date1: "{{ item.expires | regex_replace('\\+00:00') }}"

Upvotes: 1

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