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vanessen
vanessen

Reputation: 1260

Instead of git checkout file one by one, checkout a whole commit

I have a situation where I committed to a branch B1. In the commit I have several files. Now I want those files to be copied to a Branch B2.

Actually I am using the following command for each file in the commit on my current branch B2:

 $ git checkout B1 path/to/file1
 $ git checkout B1 path/to/file2
 ......
 $ git checkout B1 path/to/fileN

I guess that there should be a syntax that will allow me to directly checkout the specific commit from branch B1 to branch B2. I tried several solutions but they are rewriting the whole branch which I do not want, nor history of the all files. I only want the state of the file in the particular commit. Overwriting is not a problem.

How to achieve this ?

Upvotes: 0

Views: 89

Answers (2)

LeGEC
LeGEC

Reputation: 51850

To get the list of files modified in commit xyz, run :

# get only the names for the diff between xyz's parent and xyz :
git diff --name-only xyz^ xyz

If you want to checkout these files only :

git checkout B1 -- $(git diff --name-only xyz^ xyz)

# for example : the files modified in the last commit on B2 :
git checkout B1 -- $(git diff --name-only B2^ B2)

Upvotes: 1

grawity_u1686
grawity_u1686

Reputation: 16247

git checkout B1 .

You have to specify a path to get what you want, so . is a path that specifies the current directory.

Upvotes: 1

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