CODEWITHSUNDEEP
phpcodeigniter
Hybrid Developer
Hybrid Developer

Reputation: 2340

CodeIgniter 4 how to load a model in the controller?

First of all, I am having very little knowledge of CodeIgniter 3 and now I am first time using the new CodeIgniter 4. For the HMVC module building, I was using MX_Controller in CI3. Now when I came to know the CI4 is by default supporting HMVC I am trying to make use of it. When I try to port my first module I am getting an error in the Controller about the constructor.

  1. How can I load my model in this controller?

  2. Can't I load my model in the constructor straight away?

Template.php [Controller]

<?php
namespace Modules\Template\Controllers; // sPiDeR adder namespace for CI4 support
//defined('BASEPATH') OR exit('No direct script access allowed');
class Template extends \CodeIgniter\Controller { // Using CI controller instead of MX Controller

    public function __construct()
    {
        parent::__construct();
        $this->load->model(array(
            'template_model'
        ));
                
    }

    public function layout($data)
    {
        $id = $this->session->userdata('id');
        $data['notifications'] = $this->template_model->notifications($id);
        $data['quick_messages'] = $this->template_model->messages($id);
        $data['setting'] = $this->template_model->setting();
        $this->load->view('layout', $data);
        //echo view('layout', $data); //sPiDeR update syntax change
    }

    public function login($data)
    {
      $data['setting'] = $this->template_model->setting();
      $this->load->view('login', $data);
    //echo view('login', $data); //sPiDeR update syntax change
    }

}

Error I am getting in Debugger

enter image description here

Upvotes: 1

Views: 15582

Answers (2)

Omkar76
Omkar76

Reputation: 1638

I'll recommend using Upgrading from 3.x to 4.x guide while you migrate your app from CI3 to CI4. All the changes you might require to convert your app from version 3 to 4 are explained in it.

Steps for upgrading models include what you need. Quoting only part relevant to question:

  1. Instead of CI3’s $this->load->model(x);, you would now use $this->x = new X();, following namespaced conventions for your component. Alternatively, you can use the model function: $this->x = model('X');.

You can load models from within the constructor if you follow one of these approaches.

Upvotes: 3

Anand Pandey
Anand Pandey

Reputation: 2025

Please use model like that its working surely.

use App\Models\Model1;
use App\Models\Model2;
    class Myclass extends Backendcontroller
    {

        public function __construct()
        {
            $this->Model1 = new Model1();
            $this->Model2 = new Model2();
        }


$foo = $this->Model3->where('bar', $bar)->findAll();

Upvotes: 4

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