CODEWITHSUNDEEP
ciotazure-sphere
Vaduganathan
Vaduganathan

Reputation: 11

When char array is passed to a method, the array looses its value

I have method which accepts "constant char*" as a parameter. But when I pass the below array to the method "*SendUartMessage(int uartFd, const char dataToSend)**" only first two hexadecimal values are showing inside the method in the parameter. To be precise as the third value is zero 0x00, it blocks the other values pass inside the method. Can any one provide solution to pass all the array value inside the method.

const char updateAllChannelData[] = { 0x01, 0x06, 0x00, 0x19, 0x00, 0x01, 0x99, 0xCD };
            SendUartMessage(uartFd, updateAllChannelData);

This is the method

static void SendUartMessage(int uartFd, const char* dataToSend)
{
    size_t totalBytesSent = 0;
    size_t totalBytesToSend = strlen(dataToSend);
    int sendIterations = 0;
    close(r1PinFd);
    r1PinFd = GPIO_OpenAsOutput(MIKROE_PWM, GPIO_OutputMode_PushPull, GPIO_Value_High);
    while (totalBytesSent < totalBytesToSend) {
        sendIterations++;

        // Send as much of the remaining data as possible
        size_t bytesLeftToSend = totalBytesToSend - totalBytesSent;
        const char* remainingMessageToSend = dataToSend + totalBytesSent;
        ssize_t bytesSent = write(uartFd, remainingMessageToSend, bytesLeftToSend);
        if (bytesSent == -1) {
            Log_Debug("ERROR: Could not write to UART: %s (%d).\n", strerror(errno), errno);
            exitCode = ExitCode_SendMessage_Write;
            return;
        }

        totalBytesSent += (size_t)bytesSent;
    }
    int c, d;

    sleep(5);
    close(r1PinFd);
    r1PinFd = GPIO_OpenAsOutput(MIKROE_PWM, GPIO_OutputMode_PushPull, GPIO_Value_Low);

    Log_Debug("Sent %zu bytes over UART in %d calls.\n", totalBytesSent, sendIterations);
}

Upvotes: 0

Views: 101

Answers (3)

chux
chux

Reputation: 153303

Can any one provide solution to pass all the array value inside the method.

In C, when an array is passed to a function, the arrray is first converted to the type and address of the first element.

const char updateAllChannelData[] = { 
    0x01, 0x06, 0x00, 0x19, 0x00, 0x01, 0x99, 0xCD };
SendUartMessage(uartFd, updateAllChannelData);

SendUartMessage() receives a pointer to updateAllChannelData[0], not the array.

For SendUartMessage() to know how much of the array to use, also pass the array element count and re-write SendUartMessage() to accept the count.

static void SendUartMessage(int uartFd, size_t count, const char* dataToSend);

const char updateAllChannelData[] = { 
    0x01, 0x06, 0x00, 0x19, 0x00, 0x01, 0x99, 0xCD };
size_t count = sizeof updateAllChannelData / sizeof updateAllChannelData[0];
SendUartMessage(uartFd, count, updateAllChannelData);

Upvotes: 0

Kevin
Kevin

Reputation: 7324

The array has a 0 byte at index 2. strlen calculates the length of a C-string, that is, a null terminated (0 byte terminated) array. Treating your array as a string, the length is 2. If you want to know the real length of the array you have to pass it as a parameter:

const char updateAllChannelData[] = { 0x01, 0x06, 0x00, 0x19, 0x00, 0x01, 0x99, 0xCD };
SendUartMessage(uartFd, updateAllChannelData, sizeof(updateAllChannelData));

static void SendUartMessage(int uartFd, const char* dataToSend, size_t totalBytesToSend)
{
   ...
}

Upvotes: 2

dbush
dbush

Reputation: 223689

You're using strlen on a character array that is not a string.

Strings in C are null terminated, meaning a byte with value 0 ends the string. You don't have a string but an array of bytes whose valid values include 0.

You need to pass the size of the array to the function as a separate parameter.

Upvotes: 0

Related Questions