CODEWITHSUNDEEP
pythonfunctionprintingsplitsentence
Aiden 1L8L
Aiden 1L8L

Reputation: 9

How can I use the split() function to figure out how many vowels there are in total?

How can I use the split() function to figure out how many vowels there are in total? How can I print the number of a, e, i, o, and u in each of these sentences? The sentence is

'I study Python programming at KAIST Center For Gifted Education'

umm.... counter is not working guys..(i mean I want you to give me details one by one, not the built-in function of the basic Python, So that it can work on other coding programs.

Upvotes: 1

Views: 65

Answers (2)

Paul P
Paul P

Reputation: 3917

I would suggest using collections.Counter(), e.g. like this:

from collections import Counter

sentence = 'I study Python programming at KAIST Center For Gifted Education'

counts = Counter(sentence)

print(counts['a'])
# 3
print(counts['A'])
# 1
print(counts['e'])
# 3
print(counts['E'])
# 1
print(counts['i'])
# 3
print(counts['I'])
# 2
print(counts['o'])
# 4
print(counts['O'])
# 0
print(counts['u'])
# 2
print(counts['U'])
# 0

If you'd like to count the vowels case-independently you can call .lower() on the sentence before passing it to Counter(), e.g.:

from collections import Counter

sentence = 'I study Python programming at KAIST Center For Gifted Education'

counts = Counter(sentence.lower())

print(counts['a'])
# 4
print(counts['e'])
# 4
print(counts['i'])
# 5
print(counts['o'])
# 4
print(counts['u'])
# 2

EDIT:

If for some reason you cannot use the collections library, strings have a count() method:

sentence = 'I study Python programming at KAIST Center For Gifted Education'

print(sentence.count('a'))
# 3
print(sentence.count('e'))
# 3
print(sentence.count('i'))
# 3
print(sentence.count('o'))
# 4
print(sentence.count('u'))
# 2

In case you'd like to count more than just vowels, it may be more efficient to "manually" count the sub-strings (i.e. vowels in your case), e.g.:

sentence = 'I study Python programming at KAIST Center For Gifted Education'

# Initialise counters:
vowels = {
    'a': 0,
    'e': 0,
    'i': 0,
    'o': 0,
    'u': 0,
}

for char in sentence:
    if char in vowels:
        vowels[char] += 1

print(vowels['a'])
# 3
print(vowels['e'])
# 3
print(vowels['i'])
# 3
print(vowels['o'])
# 4
print(vowels['u'])
# 2

Upvotes: 1

user15801675
user15801675

Reputation:

Check this?

from collections import Counter
x='I study Python programming at KAIST Center For Gifted Education'
x=[a for a in x]
vowels=['a','e','i','o','u']
check_list=[]
for check in x:
    if check.lower() in vowels:
        check_list.append(check.lower())
count=Counter(check_list)
print(count)

Upvotes: 0

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