CODEWITHSUNDEEP
c++
bro grammer
bro grammer

Reputation: 3

timer to calculate seconds not being implemented properly

I am making a timer to calculate the number of seconds until the user presses 3 however the program doesn't work, and no value is saved in the integer variable 'sec'. where am i wrong? I have include windows.h and ctime.h Here's the code:

       void func(){
       int sec=0
       cout<<"Press 3 to end Timer";
                cin>>t;
                
                while(t!=3){
                Sleep(1);
                sec++;}
                
                if(t==3)
                {
                    cout<<"Timer ended";
                }

}

Upvotes: 0

Views: 40

Answers (1)

Joseph Larson
Joseph Larson

Reputation: 9078

This is because cin >> t is blocking. That is, execution doesn't move to your while-loop until the input is complete.

Something like this would work:

#include <chrono>

// This is just to make the example cleaner.
using namespace chrono;

...

system_clock::time_point startTime = system_clock::now();

cin >> t;

system_clock::time_point endTime = system_clock::now();
milliseconds duration = time_point_cast<milliseconds>(endTime - startTime);

At this point, duration.count() is the number of milliseconds spent waiting for input. You can do some math to turn it into seconds, or you could use seconds instead like this:

seconds duration = time_point_cast<seconds>(endTime - startTime);

but in this case, 2.9 seconds will show up as 2 seconds (I think). So I'd do this to output it:

cout << "Duration: " << (double)duration.count() / 1000.0 << endl;

Or something along those lines. I'm typing this raw, so there might be typos.

Upvotes: 2

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