CODEWITHSUNDEEP
javaregexstringsplit
shirohoo
shirohoo

Reputation: 91

How should i get result used regex and split method in Java?

I have a String

String s = "XXXX....XXX.....XX";

I want the following results.

String[] strings = {"XXXX", "XXX", "XX"};

I tried the following.

String[] split = s.split("[\\.*]");

i got the result

enter image description here

How should I do this if possible?

Upvotes: 2

Views: 56

Answers (2)

Ryszard Czech
Ryszard Czech

Reputation: 18611

Another way:

String[] results = string.split("(?:\\Q.\\E)+");

See regex proof.

EXPLANATION

--------------------------------------------------------------------------------
  (?:                      group, but do not capture (1 or more times
                           (matching the most amount possible)):
--------------------------------------------------------------------------------
    \Q                       start of a literal string pattern
--------------------------------------------------------------------------------
    .                        a literal dot
--------------------------------------------------------------------------------
    \E                       end of a literal string pattern
--------------------------------------------------------------------------------
  )+                       end of grouping

Upvotes: 1

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626893

To split with multiple dots and avoid empty items, you can use

String[] chunks = s.split("\\.+");
String[] chunks = s.replaceFirst("^\\.+", "").split("\\.+");

NOTE: the replaceFirst("^\\.+", "") is necessary in case there are leading dots. If you are sure there can be no leading dots, you may use s.split("\\.+") alone.

Details:

  • ^ - start of string
  • \.+ - one or more dot chars (in a Java string literal, the backslash is doubled)

See the Java demo online:

String s = "...XXXX....XXX.....XX...";
String[] chunks = s.replaceFirst("^\\.+", "").split("\\.+");
System.out.println(Arrays.toString(chunks));

Upvotes: 3

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